Which of the I-values satisfy the following inequality?
2 answers:
Answer:
Simplifying
x = 2x + -21
Reorder the terms:
x = -21 + 2x
Solving
x = -21 + 2x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-2x' to each side of the equation.
x + -2x = -21 + 2x + -2x
Combine like terms: x + -2x = -1x
-1x = -21 + 2x + -2x
Combine like terms: 2x + -2x = 0
-1x = -21 + 0
-1x = -21
Divide each side by '-1'.
x = 21
Simplifying
x = 21
Answer:
The answers are options A and B
First solve the inequality
7x < 21
Divide both sides by 7
That's
7x/7 < 21/7
x < 3
The values that satisfy the inequality are
1 and 2 since they are both less than 3
Hope this helps you.
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Answer:
Step-by-step explanation:
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(6-8)^2+(4+5)^2
d^2=4+81
d^2=85
d=(85)^(1/2)
d=9.22 (rounded to nearest hundredth)
In decimal form it's .75 and that's all you can make it
4/5 because 8/10 is equal to 4/5 which is the simplest form<span />
Here is the graph answer choices
