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nata0808 [166]
3 years ago
8

While you work on the customer's printer, he continues chatting about his network and problems he's been experiencing. One compl

aint is that his Internet service slows down considerably in the evening. You suspect you know the cause of this problem: His neighbors arrive home in the evening and bog down the ISP's local infrastructure. To be sure, you take a quick look at the back of his modem. What type of cable connected to the WAN port would confirm your suspicions and why
Computers and Technology
1 answer:
Tanya [424]3 years ago
8 0

Answer:

Most likely a serial cable. The type of cable is dependent on the WAN port, we can have serial or CAT 6 cable.

Explanation:

You might be interested in
1:A presentation program which is developed by Microsoft
LekaFEV [45]
Option 3: PowerPoint.
4 0
2 years ago
Read 2 more answers
As Kaydence reads a chapter in her anthropology text, she draws a network diagramming the relationships among the concepts descr
german

Answer:

visual encoding

Explanation:

According to my research on the three types of encoding methods, I can say that based on the information provided within the question Kaydence is best described as capitalizing on visual encoding. Which is the act of associating a certain something with a picture in order to store it into memory, as opposed of associating it with sound or words. In this situation Kaydence is associating it with a networking diagram she drew.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

5 0
3 years ago
Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static
yKpoI14uk [10]

Answer:

Hope this helped you, and if it did , do consider giving brainliest.

Explanation:

import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}

7 0
2 years ago
Do all the countries have the same date format?
alexandr402 [8]
No they don’t have the same data format.
4 0
3 years ago
The function below takes one parameter: an integer (begin). Complete the function so that it prints the numbers starting at begi
arlik [135]

Answer:

Program is in C++

Explanation:

C++ Code

1) By using For Loop

void forLoopFunction(int value){

for(int start=value; start>0; start--){

 cout<<start<<endl;

}

}

Explanation

Start for loop by assigning the loop variable to parameter value and condition will be that loop variable will be greater then 0 and at the end decrements the loop variable.

2) By usin WhileLoop

void whileLoopFunction(int value){

 while(value>0){

 cout<<value<<endl;

 value--;

 }

}

Explanation

In while loop first add the condition as variable must be greater then 0 and then print the value with endl sign to send the cursor to next line and at the end of the loop decrements the variable.

8 0
2 years ago
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