Answer:
A. 1 rectangle, 2 triangles
B. AB = AE = 5
C. 36.5 square units
Step-by-step explanation:
<h3>A.</h3>
The attached figure shows 1 rectangle (square) and two triangles.
__
<h3>B.</h3>
These sides are aligned with the grid, so their length is simply the difference in coordinates along the line:
AB = 2 -(-3) = 5
AE = 3 -(-2) = 5
__
<h3>C.</h3>
The area of the square is ...
A = s^2 = 5^2 = 25
The area of triangle BCF is ...
A = 1/2bh = 1/2(3)(5) = 15/2
The area of triangle CDE is ...
A = 1/2bh = 1/2(8)(1) = 4
The total area is the sum of the areas of the square and two triangles:
total area = 25 +7.5 +4 = 36.5 . . . square units
_____
<em>Additional comment</em>
We note that segment CE divides the figure into <em>trapezoid</em> ABCE and <em>triangle</em> CDE. The trapezoid has bases 5 and 8, and height 5, so its area is ...
A = 1/2(b1 +b2)h = 1/2(5 +8)(5) = 32.5
Triangle CDE has the same area as computed above, 4 square units. So, the total area of the figure is ...
32.5 +4 = 36. 5 . . . . square units
Answer:
A is the answer
12 in
first substitute the variables
then 78=1/2h(5 + 8)
this makes it an equation
add similar terms which equals to
78=1/2xhx13
then divide both sides by 13
6=1/2xh
lastly divide both sides by 1/2
12=h
Step-by-step explanation:
proof
A=1/2x12(5 + 8) then
A=1/2x12x13 then
A=6x13 then
A= 78in^2
2x = 2 * 3 = 6
6^2 = 6*6 = 36
36 + 3 = 39
Answer: 39
Answer:
- high tide occurs at 12 noon and 12 midnight
- Low tide occurs at 6 a.m and 6 p.m
- maximum depth value = 20 ft
- Minimum depth value = 15 ft
Step-by-step explanation:
The depth is modelled as;
y = 20 + 5 cos (πt/6)
We are told that t = 0 represents 12:00 midnight.
This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.
Max depth value is;
y = 20 + 5(0)
y = 20 ft
Minimum depth value will be the low tide and it will be when the cos function is equal to -1.
Thus;
y = 20 + 5(-1)
y = 15 ft
Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;
12 noon
Also, let's check for low tide.
Let's try t = 6 which means 6 a.m
Thus;
y = 20 + 5 cos (π(6)/6)
y = 20 + 5 cos π
Cos π has a value of -1
Thus;
y = 20 + 5(-1)
y = 20 - 5
y = 15 ft
Thus;
Low tide occurs at 6 a.m and 6 p.m
The cost of the 15 percent of replaced vacuum cleaner which are sold under warranty is $3,681,384. Option b is correct.
<h3>What is percentage ?</h3>
Percentage of a number is the part of the number expressed in the in every hundred. Percentage of a number is expressed with the symbol '%'.
A vacuum cleaner costs $68, and the full-replacement extended warranty costs $22.
The manufacturer sells 360,920 vacuum cleaners under warranty and must replace 15% of them to honor the warranties. Thus, the number of vecuum cleaner replaced by manufacturer is,

The cost of one vacuum cleaner is $68. Thus the cost of 54138 vcacuum cleaner is,

Hence, the cost of the 15 percent of replaced vacuum cleaner which are sold under warranty is $3,681,384. Option b is correct.
Learn more about the percentage here;
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