I WILL IVE U 5 STARS
1 answer:
Answer:
A. 1 rectangle, 2 triangles
B. AB = AE = 5
C. 36.5 square units
Step-by-step explanation:
<h3>A.</h3>The attached figure shows 1 rectangle (square) and two triangles.
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<h3>B.</h3>These sides are aligned with the grid, so their length is simply the difference in coordinates along the line:
AB = 2 -(-3) = 5
AE = 3 -(-2) = 5
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<h3>C.</h3>The area of the square is ...
A = s^2 = 5^2 = 25
The area of triangle BCF is ...
A = 1/2bh = 1/2(3)(5) = 15/2
The area of triangle CDE is ...
A = 1/2bh = 1/2(8)(1) = 4
The total area is the sum of the areas of the square and two triangles:
total area = 25 +7.5 +4 = 36.5 . . . square units
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<em>Additional comment</em>
We note that segment CE divides the figure into <em>trapezoid</em> ABCE and <em>triangle</em> CDE. The trapezoid has bases 5 and 8, and height 5, so its area is ...
A = 1/2(b1 +b2)h = 1/2(5 +8)(5) = 32.5
Triangle CDE has the same area as computed above, 4 square units. So, the total area of the figure is ...
32.5 +4 = 36. 5 . . . . square units
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Answer:
∠Q = 63.4º, PQ = 2, QO = 4.47
Step-by-step explanation:
A triangle is a polygon with three sides and three angles. There are different types of triangles such as the equilateral triangle, isosceles triangle, scalene triangle, right angled triangle.
Triangle POQ is a right angled triangle because ∠P = 90°. Also, ∠O = 26.6°.
Therefore in ΔPOQ: ∠P + ∠O + ∠Q = 180° (sum of angles in a triangle).
90 + 26.6 + ∠Q = 180
∠Q + 116.6 = 180
∠Q = 180 - 116
∠Q = 63.4°
We can find PQ and QO using sine rule. Sine rule for ΔPOQ is given as:
