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exis [7]
3 years ago
9

Which is equivalent to (9 y squared minus 4 x)(9 y squared + 4 x), and what type of special product is it?

Mathematics
1 answer:
puteri [66]3 years ago
5 0

Answer:

(9y^2-4x)\,(9y^2+4x)=81y^4-16x^2

and it is the special factor product that leads to a difference of squares

Step-by-step explanation:

The product: (9y^2-4x)\,(9y^2+4x)

is a product of the form:

(a-b)\,(a+b) = a^2-b^2

which leads as shown to a difference of squares. So they binomials (a-b) and (a+b)  are the factors of the difference of squares a^2-b^2.

In our case, the product:

(9y^2-4x)\,(9y^2+4x)= (9y^2)^2-(4x)^2=81y^4-16x^2

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