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3 years ago

I NEED HELP ,PLAESE AYUDAAAAA POR FAVOR

Mathematics

1 answer:

algol133 years ago

3 0

Answer:

Step-by-step explanation:

First off, if side BC and side EC are congruent, then this is an isosceles triangle. It then goes to follow by the Isosceles Triangle Theorem that angle EBC is also 67 degrees. By the Triangle Angle-Sum Theorem then, angle BCE is 180 - 67 - 67 which is 46 degrees. Angle BCE is supplementary to angle FCA which means they add up to equal 180, so angle FCA is 180 - 46 = 134.

Angle FCA = 134

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1.9(2.3n+6)+10.45>43.7

Ulleksa [173]

Answer:

4.27n+21.4

Step-by-step explanation:

8 0

3 years ago

a sample of unknown liquid has a volume of 12.0ml and a mass off 6g, what is its density? and how did you do the problem?

maw [93]

Answer:

Step-by-step explanation:

The equation for solving for density is:

Density = mass / volume

Then plug in the values:

Density = 6 g / 12 mL

Divide and don't forget the units!

Density = 0.5 g/mL

5 0

3 years ago

The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati

Ksivusya [100]

<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

$\dfrac{24}{25}$

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

$Perimeter\ of\ R=2(2x+3x)$

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

$Perimeter=2(L+B)$ )

Hence, we get:

$Perimeter\ of\ R=2(5x)$

i.e.

$Perimeter\ of\ R=10x$

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

$\text{Perimeter\ of\ square}=4s$

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

$4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}$

Now, we know that the area of a square is given by:

$\text{Area\ of\ square}=s^2$

and

$\text{Area\ of\ Rectangle}=L\times B$

Hence, we get:

$\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}$

and

$\text{Area\ of\ Rectangle}=2x\times 3x$

i.e.

$\text{Area\ of\ Rectangle}=6x^2$

Hence,

Ratio of the area of region R to the area of region S is:

$=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}$

6 0

3 years ago

Read 2 more answers

While setting up a fireworks display, you have a tool at the top of the

atroni [7]

Answer:

0.79 sec

Step-by-step explanation:

Given there is a tool at the top of the building which is dropped by a worker and it follows the following equation at every instant of time .

$h(t)=-16t^{2} +h_{0}$

where $h_{0} =10 feet$

We know that this height is measured from the base of the building which means that when the tool reaches the bottom of the building it has h = 0 feet.

Let this be done at time t

h(t) = 0

$-16t^{2} +10=0$

$t^{2} =\frac{10}{16}$

$t=\frac{\sqrt{10} }{4}$

t = 0.79 sec

Therefore the total time taken by the tool to reach the bottom of the building is 0.79 sec.

8 0

3 years ago

(8Q) Tell whether the function exhibits damped oscillation. If it does, identify the damping factor and tell whether the damping

dezoksy [38]

Answer:

Option c.

No damping

Step-by-step explanation:

We can easily solve this question by using a graphing calculator or any plotting tool.

The function is

f(x) = (√11)*cos(3.7x)

Which can be seen in the picture below

We can notice that f(x) is a cosine with maximum amplitude of (√11). Neither this factor nor the multiplication of x by 3.7 serve as a damping factor since they are constants.

f(x) does not present any dampening

5 0

3 years ago

Read 2 more answers