Ask question

Ask question

All categories

valentinak56 [21]

3 years ago

11

I NEED HELP ,PLAESE AYUDAAAAA POR FAVOR

1 answer:

algol133 years ago

3 0

Answer:

Step-by-step explanation:

First off, if side BC and side EC are congruent, then this is an isosceles triangle. It then goes to follow by the Isosceles Triangle Theorem that angle EBC is also 67 degrees. By the Triangle Angle-Sum Theorem then, angle BCE is 180 - 67 - 67 which is 46 degrees. Angle BCE is supplementary to angle FCA which means they add up to equal 180, so angle FCA is 180 - 46 = 134.

Angle FCA = 134

You might be interested in

Y/7=2 <br> helpppppppppppppp

Natali5045456 [20]

Answer:

y=14

Step-by-step explanation:

1.Multiply all terms by the same value to eliminate fraction denominators

2. Simplify it and it gives you 14

6 0

3 years ago

Sunil earns $12 in one hour d=hours and h=hours

Dennis_Churaev [7]

To find out how much Sybil would make in a certain amount of time, the equation would be:

h * 12

(hours times number of dollars per hour, which is 12)

Hope this helps!! :)

4 0

3 years ago

A city planner wants to build a road parallel to 2nd Ave . What is the slope of the new road?

jenyasd209 [6]

Answer: no idea

Step-by-step explanation:

5 0

3 years ago

Answer the 3 questions PLEASE

liberstina [14]

8. it’s skewed right
9. The spread is 21 to 100
10.the center is 80 or 81

3 0

3 years ago

The hypotenuse of a right triangle is 1 centimeter longer than one side and 4 centimeters longer than three times the other side

snow_tiger [21]

Answer:

$Hypotenuse = 25cm$

$Opposite = 24cm$

$Adjacent = 7cm$

Step-by-step explanation:

Represent:

The opposite with a
The adjacent with b
The hypotenuse with c

Given that:

$c = 1 + a$

$c = 4 + 3b$

Required

Solve for a, b and c

$c = c$

So, we have:

$1 + a = 4 + 3b$

Subtract 1 from both sides

$a = 4 -1 + 3b$

$a = 3 + 3b$

Apply Pythagoras Theorem

$c^2 = a^2 + b^2$

Substitute 3 + 3b for a and 4 + 3b for c

$(4 + 3b)^2 = (3 + 3b)^2 + b^2$

Open brackets

$16 + 12b+12b+9b^2 = 9 + 9b+9b+9b^2 +b^2$

$16 + 24b+9b^2 = 9 + 18b+10b^2$

Collect Like Terms

$10b^2 - 9b^2 + 18b - 24b + 9 - 16 = 0$

$b^2 - 6b -7 = 0$

Expand

$b^2 +b-7b-7=0$

Factorize:

$b(b+1)-7(b+1) =0$

$(b-7)(b+1) = 0$

Split:

$b - 7 = 0\ or\ b+1=0$

$b = 7\ or\ b=-1$

But the adjacent of a triangle can't have a negative measurement.

So:

$b = 7$

Recall that:

$c = 4 + 3b$

$a = 3 + 3b$

Substitute 7 for b in the above expressions

$c = 4 + 3 * 7$

$c = 4 + 21$

$c = 25$

$a = 3 + 3 * 7$

$a = 3 + 21$

$a = 24$

Hence, the dimensions of the triangle are:

$Hypotenuse = 25cm$

$Opposite = 24cm$

$Adjacent = 7cm$

5 0

3 years ago