<span>Quartiles are generally more reliable for judging outliers than mean and standard deviations for 2 reasons. The mean is simply the average of all of the numbers, meaning that an outlier can easily be obscured by the masses. Standard deviation is a better method, however only going over by one standard deviation in either direction would also mask an outlier. A strong outlier however will pull a quartile farther in that direction than would normally be expected.</span>
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Answer with explanation:</h2>
Given : The proportion of New Zealanders consume five or more servings of soft drinks per week :
a) The number of survey respondents reported that they consume five or more servings of soft drinks per week = 2006
b) Confidence interval for population proportion (p) :
, where 
= Sample proportion.
n= Sample size.
z* = Critical value.
For n= 2006 , and critical value for 95% confidence interval : z* = 1.96
Then , the required confidence interval will be :
i.e. A 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. = 
c) 
176\times100\%)[/tex]
d) The estimate might be biased because the survey is taken online that means offline New Zealanders are out of consideration.
<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length. Orient the base of this triangle so that it's horizontal, and represent its length by b. Let h represent the height of the triangle. Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.
Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2. Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).
The length of one of the legs is the sqrt of [5sqrt(2)]^2+[5sqrt(2)]^2, or
sqrt(25(2)+25(2)) = sqrt(100) = 10.
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8 1/4 is given as a positive number so you could write it as +8 1/4
The opposite of positive is negative, so you would have -(+8 1/4)
The answer is A
Step-by-step explanation: What they mean is if you were to say put all that data onto a graph, any kind of graph. What graph would you chose, and why? How you would work through this kind of problem, or at least how I would approach it weight out the pros and cons of each graph, or put some data on different graphs and see what works best. On the contrary if you have a rough idea of how each graph would look like you would just chose the one you think conveys the information best. I think they're is a best answer, but no wrong answer, you can make an argument for most graphs if you try, so just chose the one you think is best, and write your reasoning.
