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2 years ago

What is the answer in these boxes

Mathematics

1 answer:

TiliK225 [7]2 years ago

4 0

Answer:

I found that the answer is (5,1)

Step-by-step explanation:

4 times x(5) is 20

3 times y(1) is 3

20 + 3 = 23

bottom equation:

x(5) -- 5y(1) = 0

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What is equivalent to 8a-7-29a-8 A. 65a+80 B. -21a-15 C. 3a D. 37a+15

Reptile [31]

Answer:

B. -21a-15

Step-by-step Explanation:

$8a-7-29a-8 \\ \\ = 8a - 29a - 7 - 8 \\ \\ = - 21a - 15$

7 0

3 years ago

Pls HELP meeee. My child needs some real help I I wish I would’ve took those college lessons.

Ksenya-84 [330]

I think the answer would be 75%, meaning that the orange juice would have a greater percentage of water.

3 0

2 years ago

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One of the formulas for calculating the correct dosage for a child is as follows: C= a/((a+12)) ∙ 180 C = child’s dosage in mill

bogdanovich [222]

So you already have the formula for calculating the dosage for child with: C = a/(a+12)x 180 ml Not sure why you have double brackets

variables are: a = child's age, so everywhere you have an "a" replace it with the age of child.

Example: 5 year old child

C = 5/(5+12)*180= 5/(17)*180 = 5/3060 = .0016 ml or milligrams

8 0

3 years ago

Consider the points A(–5, 3) and B(–2, 5).

MariettaO [177]

Answer:

New coordinates for A - (2, -5)

New coordinates for B - (5, -3)

Step-by-step explanation:

When translating a point to the 7 units right, you must add 7 to the x coordinate. When translating a point 8 units down you must subtract 8 from the y coordinate.

4 0

2 years ago

Items produced by a manufacturing process are supposed to weigh 90 grams. The manufacturing procon

Annette [7]

Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of 90 grams, hence $\mu = 90$ .

The standard deviation is of 1 gram, hence $\sigma = 1$ .

We want to find the probability of an item differing more than 3 grams from the mean, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3}{1}$

$Z = 3$

The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.

Looking at the z-table, Z = -3 has a p-value of 0.0013.

2 x 0.0013 = 0.0026

0.0026 x 100% = 0.26%

0.26% of the items will either weigh less than 87 grams or more than 93 grams.

For more on the normal distribution, you can check brainly.com/question/24663213

4 0

2 years ago