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3 years ago

I need the answer to number 4

Mathematics

1 answer:

zloy xaker [14]3 years ago

5 0

Answer: 6.3

Step-by-step explanation

I did this today and it's easy but you have to show a lot of work well I did but you don't have to you can just circle it in

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1. Look for a pattern in the first three equations. Then, fill in the missing numbers in the rest of the

Alla [95]

Answer:

1=1 times 2/2 1 + 2=2 times 3/2 1 +2+3=3 times 4/2 1+2+3+4=4 times 5/2 1+2+3+4+5=5 times 6/2

4 0

3 years ago

Please help with this question

Vladimir [108]

The answer is c because when you have 1 number and a variable(s) you just add the number to the variable(s)

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2 years ago

Read 2 more answers

Fill in the Blanks

tatyana61 [14]

Answer: This would fill 4 and 4/9 containers.

Explanation:

Since we have given that

Quantity of walnuts in a container is given by

$6\frac{2}{3}=\frac{20}{3}\ pounds$

Quantity of walnuts which divided equally into containers is given by

$1\frac{1}{2}=\frac{3}{2}\ pounds$

Now, number of containers they would fill is given by

$\frac{\frac{20}{3}}{\frac{3}{2}}=\frac{20\times 2}{3\times 3}=\frac{40}{9}$

When we change it into mixed fractions we get,

$\frac{40}{9}=4\frac{4}{9}$

So, blank will be filled with '4'.

7 0

3 years ago

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How to graph an inequality y<1-2x

miskamm [114]

Answer:

Step-by-step explanation:

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3 years ago

7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)

serg [7]

Answer:

$-\frac{x^2y^2}{2}$

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

$\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}$

Multiply the numerators :

$\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}$

Multiply the denominators :

$\frac{-18x^6y^4z^3}{36x^4y^2z^3}$

Apply the negative rule :

$-\frac{18x^6y^4z^3}{36x^4y^2z^3}$

Cancel the common factor which is 18 :

$-\frac{x^6y^4z^3}{2x^4y^2z^3}$

Apply the addition exponent rule :

$\frac{y^4z^3x^{6-4} }{2y^2z^3}$

Subtract :

$\frac{x^2y^4z^3 }{2y^2z^3}$

Apply the rule for y :

$\frac{x^2y^{4-2} z^3 }{2z^3}$

Subtract :

$\frac{x^2y^2z^3 }{2z^3}$

Cancel the common factor of z^3 :

$-\frac{x^2y^2}{2}$

5 0

3 years ago