Answer:
A): f(x) = (x – 1)² + 2
Step-by-step explanation:
The quadratic function, f(x) = (x – 1)² + 2 is in <u>vertex form</u>: y = a(x - h)² + k, where:
- The vertex of the graph is (h,k).
- The value of <em>a</em> determines whether the graph opens up or down. If <em>a</em><em> </em>is <u>positive</u>, the graph opens up and the vertex is its minimum point. If <em>a </em>is <u>negative</u>, then the graph opens down, and the vertex is its maximum point.
- The value of <em>h</em> determines how far left or right the parent function is translated.
- The value of<em> k</em> determines how far up or down the parent function is translated.
The function, f(x) = (x – 1)² + 2, provides the pertinent information that allows us to determine the parabola's <u>minimum value</u>, as the value of <em>a</em> is a <u>positive</u>, which implies that the parabola is <em>upward facing</em>, and the vertex, (1, 2) is the minimum point.
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Step-by-step explanation:
all work is shown and pictured
Answer:
P= 4a would be the answer
Answer:
<h2>

</h2>
Step-by-step explanation:









<h3>
Answer: 5/9</h3>
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Explanation:
means that the 5's go on forever because of that horizontal bar over top. So we can write it as 
The three dots indicate it goes on forever following that pattern.
Let
x = 0.55555....
Multiply both sides by 10 to move the decimal point 1 spot to the right
10x = 5.55555....
Notice how both x and 10x involve a decimal number such that we have a string of 5's going on forever. If we subtract the two equations, then 10x-x becomes 9x, while the (5.55555....) - (0.55555....) simplifies to 5. The decimal portions cancel out when we subtract since they line up perfectly. We're effectively subtracting 5-0 when we cross off the decimal portions.
After those subtractions, we're left with 9x = 5 which solves to x = 5/9 when you divide both sides by 9.
Use of a calculator should show that 5/9 = 0.555555.... to help confirm the answer. Your calculator may show the last digit to be a 6 instead of a 5, but this is due to rounding. Ideally you should have a string of infinitely many 5's, but the calculator can only how so many digits.