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julsineya [31]
3 years ago
13

What equation results after distribution and combining like terms? 3−(2+9)= 4+2−11?

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0
8=5 is the answer!!!!!
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Which equation gives the value of the circumference, C, of a circle with a diameter of 56 feet?
Keith_Richards [23]

Answer:175.84 ft

Step-by-step explanation: the equation would be diameter times pi

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which has the greater volume: Prism with a length of 5 inches, a width of 4 inches, and a height of 10, or a prism with a length
GuDViN [60]
Since you have to multiple. L×W×H....

The first one has a volume of 400 and the second has a volume of 400...so both prisms have an equal volume but have a differnet shape
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2. Find the perimeter of a rectangle of<br> Length 13m with an area of 65m
I am Lyosha [343]

Answer:

Perimeter = 36m

Step-by-step explanation:

Area = l x w

65m = 13m x w

5m = w

Perimeter = 2(l + w)

Perimeter = 2(13m + 5m)

Perimeter = 36m

3 0
3 years ago
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The odometer in your mother’s car reads 3440 miles less than the odometer in your uncle’s car. Your mother’s odometer reads 2958
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6 0
3 years ago
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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
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