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3 years ago

BELL RINGER - 12/16/2020

Mathematics

2 answers:

Trava [24]3 years ago

5 0

Answer:

There is a 6% chance

Step-by-step explanation:

user100 [1]3 years ago

4 0

Answer:

6% chance

Step-by-step explanation:

12+19+14+15 = 60 60 divided by 100 = 0.6 = 6%

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What do you call when a relation with each x value has one y value

Nitella [24]

When each x value has only one y value, the relation is a function

5 0

3 years ago

Adding unlike fractions<br><br> 1/15+38/100

Daniel [21]

Answer:

134/300 or 67/150

Step-by-step explanation:

the LCM of 15 and 100 is 300. 15 *20 is 300 so we multiply both the numerator and denominator of 1/15 by 20 to get 20/300, with 38/100 we multiply by 3 to get 114/300. Now we add 20/300 and 114/300 to get 134/300 which has a common factor of 2 so we can simply it to 67/150

4 0

3 years ago

How do you factor 2x^3+5y^3

Pavel [41]

All you do is...
$\mathrm{Apply\:sum\:of\:cubes\:rule:\:}x^3+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)$

$2x^3+5y^3=\left(\sqrt[3]{2}x+\sqrt[3]{5}y\right)\left(\left(\sqrt[3]{2}\right)^2x^2-\sqrt[3]{2}\sqrt[3]{5}xy+\left(\sqrt[3]{5}\right)^2y^2\right)$
$\left(\sqrt[3]{2}x+\sqrt[3]{5}y\right)\left(\left(\sqrt[3]{2}\right)^2x^2-\sqrt[3]{2}\sqrt[3]{5}xy+\left(\sqrt[3]{5}\right)^2y^2\right) \ \textgreater \ Refine$

$\left(\sqrt[3]{2}x+\sqrt[3]{5}y\right)\left(2^{\frac{2}{3}}x^2-\sqrt[3]{10}xy+5^{\frac{2}{3}}y^2\right)$

Hope this helps!

4 0

3 years ago

What ratios are equivalent to 2 : 7?

vaieri [72.5K]

Answer:

4:14, 6:21, 8:28

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Consider the circle of radius 5 centered at (0,0), how do you find an equation of the line tangent to the circle at the point (3

Flauer [41]

$\text{We know that the tangent at any point on a circle is perpendicular}\\
\text{to the radius at that point.}\\
\\
\text{so first we find the equation of the line joining (0,0) and (3,4)}\\
\text{and then using the slope, we find the line perperndicular to it at (3,4)}\\
\\
\text{the equation of the line passing through (0,0) and (3,4) is}\\
\\
y-0=\frac{4-0}{3-0}(x-0)$

$\Rightarrow y=\frac{4}{3}x\\
\\
\text{so the slope of radius is }m=\frac{4}{3}.\\
\\
\text{we know that the product of the perpendicular lines is }-1. \\
\\
\text{so the slope of the perpendicular line would be}=-\frac{1}{4/3}=-\frac{3}{4}\\
\\
\text{So the equation of the tangent line has slope }-\frac{3}{4} \text{ and}\\
\text{passing through (3,4). so equation of tangent line is}$

$y-4=-\frac{3}{4}(x-3)\\
\\
\Rightarrow y-4=-\frac{3}{4}x+\frac{9}{4}\\
\\
\Rightarrow y=-\frac{3}{4}x+\frac{9}{4}+4\\
\\
\Rightarrow y=-\frac{3}{4}x+\frac{9+16}{4}\\
\\
\text{so the equation of tangent line is:} y=-\frac{3}{4}x+\frac{25}{4}$

5 0

4 years ago