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schepotkina [342]
3 years ago
12

The angles below form a linear par. What is the measure of angle abc

Mathematics
2 answers:
Elanso [62]3 years ago
5 0

Answer:

180-48

132

Hope this helps!

Marat540 [252]3 years ago
4 0

Answer:

ABC =132

Step-by-step explanation:

The angles form a straight line which is 180 degrees

ABC + BCD = 180

ABC + 48 = 180

Subtract 48 from each side

ABC = 180-48

ABC =132

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3 + (5 + 4) = 3+ (4 + 5) illustrates which property?​
o-na [289]

Answer:

Distributive

Step-by-step explanation:

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3 years ago
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What statement regarding the diagram is true?
kumpel [21]
I believe the second one right, because if I remember two opposite angles of an outside angle = the outside angle.
8 0
3 years ago
Who was found the math​
Zolol [24]
<h3>Answer:</h3>

  • Math is not discovered, It's Invented.

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✍︎ꕥᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴꕥ

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4 0
2 years ago
Joe Popoff, a collection agent, collected 90% of a debt of $5,600.00 that had been overdue 90 days. This collection rate was 5%
sergey [27]
<span>You are given the debt collected by Joe Popoff with a 90% of a debt of $5,600.00 that had been overdue 90 days. This collection rate was 5% more than the average collection rate for that agent. The agent charged 25% commission. You are asked to find the net proceeds. 

Amount collected
= $5,600 * 0.90
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7 0
2 years ago
Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a
Mashutka [201]

Answer:

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

Step-by-step explanation:

Given

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Required

Make the denominator equal

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Factorize the denominator

\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}

\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}

\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}

\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}

<em>The expression now have the same denominator</em>

7 0
3 years ago
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