Answer:
189 components must be sampled.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1 - 0.99}{2} = 0.005](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1%20-%200.99%7D%7B2%7D%20%3D%200.005)
Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 2.575.
Now, find the margin of error M as such
![M = z\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
Assume that component lifetimes are normally distributed with population standard deviation of 16 hours.
This means that ![\sigma = 16](https://tex.z-dn.net/?f=%5Csigma%20%3D%2016)
How many components must be sampled so that a 99% confidence interval will have margin of error of 3 hours?
n components must be sampled.
n is found when M = 3. So
![M = z\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![3 = 2.575\frac{16}{\sqrt{n}}](https://tex.z-dn.net/?f=3%20%3D%202.575%5Cfrac%7B16%7D%7B%5Csqrt%7Bn%7D%7D)
![3\sqrt{n} = 2.575*16](https://tex.z-dn.net/?f=3%5Csqrt%7Bn%7D%20%3D%202.575%2A16)
![\sqrt{n} = \frac{2.575*16}{3}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cfrac%7B2.575%2A16%7D%7B3%7D)
![(\sqrt{n})^2 = (\frac{2.575*16}{3})^2](https://tex.z-dn.net/?f=%28%5Csqrt%7Bn%7D%29%5E2%20%3D%20%28%5Cfrac%7B2.575%2A16%7D%7B3%7D%29%5E2)
![n = 188.6](https://tex.z-dn.net/?f=n%20%3D%20188.6)
Rounding up:
189 components must be sampled.
Answer:lol so true
Step-by-step explanation:
Answer:
second box is 5 and third bo is 40 and forth box is 0.25 I think! Sorry if it’s wrong!
Step-by-step explanation:
you divide them all by four.
Step-by-step explanation:
Those activities which directly or indirectly affect the people living in a society or all the social being are called social evils .
hope it is helpful to you ☺️
X=11ft
25-6=14
So ur answer is actually 3