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aleksley [76]
3 years ago
15

What is always included in a comparative investigation?

Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
4 0
These all seem right
Strike441 [17]3 years ago
3 0

Answer:

answer b

Explanation:

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Calculate the change in energy of an atom that emits a photon of wavelength 2.21 meters. (Planck’s constant is 6.626 x 10-34 jou
sp2606 [1]
Change in energy is E=hc/wavelength of emitted photon
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4 years ago
Is petroleum potential or kinetic energy
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Petroleum is a potential.
yeah that's my guess.
8 0
3 years ago
What mass of copper is equivalent to 0.7moles?​
Shkiper50 [21]
I hope thus equations help


1. How many atoms are in 6.5 moles of zinc?
1 mole = atomic mass (g)
6.5 moles 6.02 x 1023 atoms = 3.9 x 1024 atoms 1 mole
2. How many moles of argon are in a sample containing 2.4 x 1024 atoms of argon?
2.4 x 1024 atoms of argon 1 mole
6.02 x 1023 atoms
3. How many moles are in 2.5g of lithium?
2.5 grams Li 1 mole 6.9 g
4. Findthemassof4.8molesofiron.
4.8 moles 55.8 g 1 mole
= 4.0 mol
= 0.36 mol
= 267.84 g = 270g

1 mole = 6.02 x 1023 atoms 1 mole = atomic mass (g)
MASS (g)
1 mole = molar mass (look it up on the PT!)
MOLE
1 mole = 6.02 x 1023 atoms
PARTICLES (ATOM)
Two Step Problems:
1. What is the mass of 2.25 x 1025 atoms of lead?
2.25 x 1025 atoms of lead 1 mole 207.2g = 6.02 x 1023 atoms 1 mole
2. How many atoms are in 10.0g of gold?
10 g gold 1 mole 6.02 x 1023 atoms = 197.0g 1 mole
PRACTICE PROBLEMS:
1. How many moles are equal to 625g of copper?
625g of copper 1 mol = 9.77 mol Cu 64 g Cu
7744.19g = 7740g
3.06 x 1022 atoms
2. How many moles of barium are in a sample containing 4.25 x 1026 atoms of barium?
4.25 x 1026 atoms of barium 1 mol = 706 mol 6.02 x 1023 atoms
3. Convert 2.35 moles of carbon to atoms.
2.35 moles 6.02 x 1023 atoms = 1.41 x 1024 atoms 1 mole
4. How many atoms are in 4.0g of potassium?
4.0 g 1 mole 6.02 x 1023 atoms = 6.2 x 1022 atoms 39.1 g 1 mole

1 mole = 6.02 x 1023 atoms 1 mole = atomic mass (g)
5. Convert 9500g of iron to number of atoms in the sample.
9500 g Fe 1 mole 6.02 x 1023 atoms = 55.8g 1 mole
6. What is the mass of 0.250 moles of aluminum?
0.250 moles 27.0g = 6.75 g Al 1 mole
7. How many grams is equal to 3.48 x 1022 atoms of tin?
3.48 x 1022 atoms 1 mole 118.7g 6.02 x 1023 atoms 1 mole
8. What is the mass of 4.48 x 1021 atoms of magnesium?
4.48 x 1021 atoms 1 mole 24.3g 6.02 x 1023 atoms 1 mole
9. Howmanymolesis2.50kgoflead?
2.50kg 1000 g 1 mol 1 kg 207.2 g
1.0 x 1026 atoms
= 6.86 g Sn
= 0.181 g Mg or 1.8 x 10-1
= 12.1 mol
10.Find the mass, in cg, of 3.25 x 1021 atoms of lithium.
3.25 x 1021 atoms 1 mol 6.9g 100cg 6.02 x 1023 atoms 1 mol 1 g
= 3.7 cg
7 0
3 years ago
I What<br>What is ment by<br>ment by covalency?​
Illusion [34]
When an element shares electrons with other atoms of the same or different elements to acquire stable electronic configuration, it is called covalency. If an atom shares 1 electron, its covalency is equal to 1. ... It needs 3 electrons to complete its octet.
5 0
3 years ago
What is the complete ionic equation of Al2(SO4)3(aq) + 2K3PO4 (aq) = 2AlPO4 (s) + 3K2SO4 (aq)?
olchik [2.2K]

Answer:

2Al^{3+} (aq) +2PO_{4}^{3-} (aq) = 2AlPO_{4} (s)

Explanation:

1. First, you want to break up the aqueous solutions into their respective ions (remember to write the charge and number of each element). Note that you can only do this to compounds marked as <em>aqueous</em>, so leave the solid be.

2Al^{3+} + 3SO_{4}^{2-} + 2K_{3}^{1+} + 2PO_{4}^{3-} = 2AlPO_{4} (s) + 3K_{2}^{1+}  +3SO_{4}^{2-}

(Technically, both Potassium ions would have a coefficient of 6. I am leaving them as they were originally just for ease)

2. Now, you want to get rid of compounds on each side that are the same. These are called spectator ions, and they are exactly as the name says: they simply "spectate" the reaction, meaning they can be removed from the complete ionic equation.

Both the sulfate and potassium ions would be considered spectator ions and would be canceled out. Once removed the equation would look like:

2Al^{3+} (aq) +2PO_{4}^{3-} (aq) = 2AlPO_{4} (s)

3. The complete ionic equation would be:

2Al^{3+} (aq) +2PO_{4}^{3-} (aq) = 2AlPO_{4} (s)

5 0
3 years ago
Read 2 more answers
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