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Ksju [112]
2 years ago
12

229.2 g of tin was heated from 46.3 to 115.7°C. How much energy was used to heat tin? (Specific heat capacity of Sn is 0.222 J/g

x °C)
Chemistry
1 answer:
Dmitriy789 [7]2 years ago
5 0

3531.23 J is the energy used to heat tin when 229.2 g of tin was heated from 46.3 to 115.7°C.

<h3>What is specific heat capacity?</h3>

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Q=mcΔT

Give data:

m=229.2 g

c=0.222 J/g x °C

ΔT=115.7°C - 46.3°C

ΔT= 69.4 °C

Putting value in the equation:

Q=mcΔT

Q=229.2 g x 0.222 J/g°C x 69.4 °C

Q= 3531.23 J

Hence, 3531.23 J is the energy used to heat tin.

Learn more about the specific heat capacity here:

brainly.com/question/27919379

#SPJ1

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marishachu [46]

Kc = concentrations of product / concentrations of reactant

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What is the equilibrium constant?

The relationship between a reaction's products and reactants with regard to a certain unit is expressed by the equilibrium constant(K) This article introduces the mathematics needed to determine the partial pressure equilibrium constant as well as how to formulate expressions for equilibrium constants. By allowing a single reaction to reach equilibrium and then measuring the concentrations of each chemical participating in that reaction, one can determine the numerical value of an equilibrium constant. it is the ratio of product concentrations to reactant concentrations. The equilibrium constant for a given reaction is unaffected by the initial concentrations because the concentrations are measured at equilibrium.

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6 0
1 year ago
If the caterpillar keeps moving at the same speed, how long will it take to travel 6cm?
Solnce55 [7]

It will take 15 s to travel 6 cm

<h3>Further explanation</h3>

Given

distance versus time graph

Required

time travel

Solution

Caterpillar motion is a straight motion with a constant speed, so that the graph between distance and time forms a diagonal line

If we look at the graph, we can determine the time taken when the distance reaches 6 cm (y axis) by drawing a line to the diagonal line and cutting the x-axis as time, and we get 15 s

Or we can also use the formula for motion at constant speed:

d = v x t

With v at point 2,5 of 2/5 m / s, so the time taken:

\tt t=\dfrac{d}{v}=\dfrac{6}{2/5}=15~s

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Please help asap.....
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