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MAVERICK [17]
3 years ago
13

Give me a hand,Solve this problem,Need everyone's help​

Chemistry
1 answer:
elixir [45]3 years ago
8 0

Answer:

A. 8.8 g.

B. 5.3 g.

C. 449 g.

Explanation:

A. Determination of the mass of CO2.

Mole of CO2 = 0.2 mole

Molar mass of CO2 = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO2 =?

Mole = mass /Molar mass

0.2 = mass of CO2 /44

Cross multiply

Mass of CO2 = 0.2 × 44

Mass of CO2 = 8.8 g

B. Determination of the mass of Na2CO3.

Mole of Na2CO3 = 0.05 mole

Molar mass of Na2CO3 = (2×23) + 12 + (3×16)

= 46 + 12 + 48

= 106 g/mol

Mass of Na2CO3 =?

Mole = mass /Molar mass

0.05 = mass of Na2CO3 /106

Cross multiply

Mass of Na2CO3 = 0.05 × 106

Mass of Na2CO3 = 5.3 g

C. Determination of the mass of Fe(OH)2.

Mole of Fe(OH)2 = 5 moles

Molar mass of Fe(OH)2 = 55.8 + 2(16 + 1)

= 55.8 + 2(17)

= 55.8 + 34

= 89.8 g/mol

Mass of Fe(OH)2 =?

Mole = mass /Molar mass

5 = mass of Fe(OH)2/89.8

Cross multiply

Mass of Fe(OH)2 = 5 × 89.9

Mass of Fe(OH)2 = 449 g.

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The image is not given in the question, it is attached below:

<u>Answer:</u> The excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

<u>Explanation:</u>

In the given image:

Red spheres represent oxygen atoms, blue spheres represent nitrogen atoms and black spheres represent carbon atoms

The combination of 1 black and 2 red spheres will represent carbon dioxide (CO_2) compound

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We are given:

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Thus, CO is considered a limiting reagent because it limits the formation of the product.

Hence, the excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

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