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sladkih [1.3K]
3 years ago
7

How do the circulatory and endocrine systems work together?

Biology
2 answers:
kolbaska11 [484]3 years ago
8 0

Answer:

It is A.  

Blood circulates hormones around the body.

Explanation: I just took the quiz and got 100%

slavikrds [6]3 years ago
7 0
The respiratory system works directly with the circulatory system to provide oxygen to the body. Oxygen taken in from the respiratory system moves into blood vessels that then circulate oxygen-rich blood to tissues and cells.
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In a group of muskmelon plants, some individuals have sour fruit and others have sweet fruit. in this group, the gene for the fr
juin [17]

Correct option(s):

(b) This muskmelon plant's genotype for the fruit taste gene is ff.

(c) This muskmelon plant is homozygous for the fruit taste gene.

A dominant allele is one that is capable of expressing itself even in the heterozygous condition and overshadows the effect of the recessive allele. It is usually denoted by a capital letter. Recessive allele on the contrary cannot express in presence of a dominant allele and is denoted by a small letter.

In the given case the fruit with a sour taste (phenotype) can have two possible genotypes (FF and Ff). The genotype of sweet taste is ff which is a homozygous condition.  

Note: Your question is incomplete, probably your complete question is “In a group of muskmelon plants, some individuals have sour fruit and others have sweet fruit. in this group, the gene for the fruit taste trait has two alleles. the allele F is for sour fruit, and the allele f is for sweet fruit. a certain muskmelon plant from this group has sweet fruit. this plant has two alleles for sweet fruit. Choose the correct option:

(a)  this muskmelon plant's genotype for the fruit taste trait is sweet fruit.

(b) this muskmelon plant's genotype for the fruit taste gene is ff.

(c) this muskmelon plant is homozygous for the fruit taste gene.”

Know more about Mendelian genetics here:

brainly.com/question/10189802

#SPJ4

7 0
2 years ago
Calculate the frequency of b cells specific for antigen a on day 36 if the antibody concentration on day 36 is about 8 × 103. (f
matrenka [14]
-The number of B cells producing the antibody is proportional to the concentration of that antibody.

-On day 16, one out of  100000 B cells are specific for antigen A
\frac{1}{100000} = 1 x 10⁻⁵ B cells

- on day 16, Antibody concentration is  2 × 10¹= 20 Antibodies
- on day 36, antibody concentration 8 × 10³.= 8000

20 antibodies ------------ 1 x 10⁻⁵ B cells
8000 antibodies--------------x

x= (8000 x 1 x 10⁻⁵)/ 20
x= 4x10⁻³ or 1 in 250 are <span>B cells specific for antigen A</span>
8 0
3 years ago
There is a healthy bacterial culture growing in the exponential phase . A technician wants to make a growth curve by making cell
emmainna [20.7K]

A) WHAT IS THE PROBLEM WITH HER PLAN?

Binary fission is one of the asexual process by which most bacteria reproduce, the binary fission brings about a doubling of the number in bacterial cells that are viable.

Generation time is that time that it will require for a cell population to divide and double, it is also known as doubling time. This Generation time varies among distinct organisms and also varies among culture conditions.

Take for instance,a fast growing bacterium that is under an ideal culture conditions has a doubling time of 20minutes and for the bacteria that is grown in a condition that is not so ideal,may have a doubling time of hours.

The major challenge/ problem with her plan is that as she takes the bacterial sample every 30minutes, and then hold the sample till the last sampling is done in the day,those bacterial cells that are collected in the initial intervals will then get divided and further gives a result that is false.

However,if those bacteria that are collected aren't stored in a culture environment that is standard,the bacterial cells may die off and thus will further bring about a false result.

2) CAN SHE DO ANYTHING TO IMPROVE THE ACCURACY OF HER RESULT?

Solution for rectifying the error in her plan;

She can go ahead and add 50-100 μl of formaldehyde to all the culture suspensions that she has and has taken every 30minutes.

As the formaldehyde will fix the bacterial cells,The optical density present in all those aliquots can then be retrieved/taken at the end of the day.

Looking at it alternatively, aliquot 1ml of the culture suspension at an interval of every 30 minutes,and then take the optical density that is OD at a wavelength of 600nm making use of spectrophotometer until the reason you get becomes static.

5 0
3 years ago
Albinism is inherited as autosomal recessive trait. The frequency of the disease in the population equals to 1:20 000. Calculate
prisoha [69]

Answer:

0.0139- frequency of heterozygotes in the population

Explanation:

Let q to the power of 2 represents the frequency of the homozygous recessive (aa) = 1/20000 = 0.00005

This, q = √q^2 = √0.00005 = 0.007

Since p + q = 1

p = 1 - 0.007 = 0.993

Using the formula: p^2 + 2pq + q^2

Where 2pq represents the frequency of the heterozygotes, thing we have

2 x 0.007 x 0.993

= 0.0139

8 0
2 years ago
The colored part of the human eye is the <br> A. retina.<br> B. iris.<br> C. pupil.<br> D. cornea.
Triss [41]
The colored part of your eye is the iris, B.
8 0
3 years ago
Read 2 more answers
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