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3 years ago

How can a rational number and irrational number when multiplied together make a irrational number ?

Mathematics

1 answer:

pochemuha3 years ago

6 0

Answer:

"The product of a rational number and an irrational number is SOMETIMES irrational." If you multiply any irrational number by the rational number zero, the result will be zero, which is rational. Any other situation, however, of a rational times an irrational will be irrational

A better statement would be:

"The product of a non-zero rational number and an irrational number is irrational

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A study table of length 2 m and breath 1.25 m in decorted with square design of size 10x 10 find the number of such designs???

7nadin3 [17]

Answer:

Step-by-step explanation:

Area of the shape of the table = Length * Breadth (Rectangular in nature)

Area of the study table = 2m * 1.25m

Converting the units to cm

Since 100cm is equivalent to 1m, hence;

Area of the study table = 200cm * 125cm

Area of the study table = 25000cm²

If the study table is decorated with square design of size 10cm x 10cm, then the area of one square of such design will be 100 cm².

The number of square designs = Area of the study table/area of one square design

= 25000/100

= 250

Hence the number of such design on the study table is 250

8 0

3 years ago

(cotx+cscx)/(sinx+tanx)

Butoxors [25]

Answer: $\bold{\dfrac{cot(x)}{sin(x)}}$

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

$\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)$

$\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)$

$\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}$

6 0

4 years ago

53,60070001 +624-7646÷7000+1,000,000,000,000-5000 million subtracted by 12+ 1,225,000 50 million trillion divided by one quadril

Iteru [2.4K]

Answer:

Solution not exists.

Step-by-step explanation:

Since in a certain step a certain amount divided by zero, an that stage the quentity is undefined. That is if,

$\frac{5360070001+624-7646}{7000+1000000000-5000,000,000}-12+122500050,000,000,000,000,000,000=X$

Then, at the next stage, $\frac{X}{0}$ is not exists, wheather after it divided by 1 or not. Thus required solution is not exists.

8 0

3 years ago

HELP PEASE ASAP 20 POINTS<br><br> What is 3x19x28/39x90x2/0

photoshop1234 [79]

Answer:

The answer is 0

Anything that ends up being divided by zero is always zero.

8 0

3 years ago

Read 2 more answers

Which figure represents an undefined term?

Fudgin [204]

In geometry, the three undefined terms are: the point, the plane and the straight line.

Since all the given graphs represent lines,we will need to choose the straight line among them.

Straight line is a line that has no start and no end.

From the choices:
Figures a and c are rays
figure b is a line segment
figure d is a straight line

Therefore, the correct choice is: D

8 0

4 years ago

Read 2 more answers