We are given two relations
(a)
Relation (R)
![R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]](https://tex.z-dn.net/?f=R%3D%5B%28%28k-8.3%2B2.4k%29%2C-5%29%2C%28-%5Cfrac%7B3%7D%7B4%7Dk%2C4%29%5D)
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k
............Answer
(b)
S = {(2−|k+1| , 4), (−6, 7)}
We know that
any relation can not be function when their inputs are same
so, we can set both x-values equal
and then we can solve for k
Since, this is absolute function
so, we can break it into two parts
we get
so,
...............Answer
Answer:
<h2>Revenue will decrease</h2>
Step-by-step explanation:
Note: the question did not provide the quantity to work with, so we will assume some values, say quantity Q= 30
Generally, it is normal for the revenue to decrease when the price of a commodity increase, this is so that buyer will have to react to adjust to the change in price.
When price increase from $50 to $60, the total revenue will decrease
let say the quantity Q1=30 , and the new quantity after price increase is Q2=20
1. The revenue PxQ before price change will be
PxQ= P1xQ1=50*30
PxQ= $1500
1. The revenue PxQ after price change will be
PxQ=P2xQ2= 60*20
P2xQ2= $1200
This clearly shows that based on the assumed data, the total revenue will drop from1500 to 1200, a total of $300 in a decrease
Answer:67
Step-by-step explanation:
Answer:
The answer would be: V1/T1=V2/T2
19/20
19/20 = 0.95
0.9 < 0.95
