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3 years ago

ENRICO PAY CHECK FOR LAST WEEK WAS FOR 633 DOLLARS. HE. PAID 17DOLLARS AN HOUR. HOW MANY HOURS DID ENRICO WORK LAST WEEK?

Mathematics

2 answers:

Elena-2011 [213]3 years ago

5 0

37 hours

633 divided by 17

Andreas93 [3]3 years ago

3 0

Enrico would have worked 37 hours last week.

Simply take the amount of money he makes, divided by the hours he worked!

Hoped this helped !! :)) -ky

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John has a boat that will travel at the rate of 15 kph in still water. He can go upstream for 35 km in the same time it takes to

Otrada [13]

Answer:

The boat traveling at 24 kph when John goes downstream.

Step-by-step explanation:

We are given the following in the question:

John has a boat that will travel at the rate of 15 kph in still water.

Let x be the speed of the current.

Speed of boat in upstream

$(15-x)\text{ kph}$

Speed of water in downstream

$(15+x)\text{ kph}$

Relation:

$\text{Speed} = \dfrac{\text{Distance}}{\text{Time}}$

We have to find the speed of boat in downstream.

Time to travel upstream for 35 km = Time to travel 140 km downstream

$\displaystyle\frac{35}{15-x}=\frac{140}{15+x}\\\\35(15+x) = 140(15-x)\\525 + 35x = 2100 - 140x\\175x = 1575\\x = 9$

Thus, speed of current is 9 kph.

Speed of boat in downstream = 15 + 9 = 24 kph.

Thus, the boat traveling at 24 kph when John goes downstream.

4 0

3 years ago

Find the equation of locus of a point which moves such that its distance from (0,2) is one third distance from (-2,3). ( I WILL

scoray [572]

Answer:

$8(x^2+y^2)-4x-30y+23=0$

Step-by-step explanation:

<u />

<u>Distance formula</u>

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let P(x, y) = any point on the locus

Let A = (0, 2)

Let B = (-2, 3)

If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

$PA=\dfrac{1}{3}PB$

Therefore, using the distance formula:

$\implies \sqrt{(x-0)^2+(y-2)^2}=\dfrac{1}{3}\sqrt{(x-(-2))^2+(y-3)^2}$

Square both sides:

$\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]$

$\implies x^2+y^2-4y+4=\dfrac{1}{9}(x^2+4x+4+y^2-6y+9)$

Multiply both sides by 9:

$\implies 9x^2+9y^2-36y+36=x^2+4x+4+y^2-6y+9$

$\implies 8x^2+8y^2-4x-30y+23=0$

$\implies 8(x^2+y^2)-4x-30y+23=0$

3 0

1 year ago

When Rachel put gas in her car she records the distance and she has driven since her last fill up and then number of gallon of g

katen-ka-za [31]

Answer:

You obviously copied the question text in an incomplete and lazy way.

I still really wanna help you on your problem.

Please either point the whole question with the possible answers or make a photograph of the problem.

7 0

3 years ago

PLZZZZ NEED HELP!!!!!

Elena-2011 [213]

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4 0

2 years ago

Line bc is represented by 3x+2y=8 line ad is represented by -3x-2y=6 what is the relationship of line bc to line ad explain the

Bas_tet [7]

Answer:

The answer is below

Step-by-step explanation:

The equation of a straight line is given by:

y = mx + b

where m is the slope of the line and b is the y intercept (value of y when x = 0).

Given the equation of two lines as $y=m_1x+b_1\ and\ y=m_2x+b_2$ , the two lines are parallel to each other if $m_1=m_2$ . Also the lines are perpendicular if

$m_1m_2=-1$

Given line BC:

3x + 2y = 8

2y = -3x + 8

y = -3x/2 + 4

Hence the slope of the line BC = -3/2

For line AD:

-3x - 2y = 6

-2y =3x + 6

y = -3x/2 - 3

Hence the slope of line AD is -3/2

Since both line BC and AD have equal slope (-3/2), hence both lines are parallel to each other

8 0

2 years ago