Question

In ΔJKL, solve for x. (4 points) Triangle JKL where angle K is a right angle. KL measures 34. JL measures x. Angle J measures 27 degrees.

Answer 1

Answer:

74.8

Step-by-step explanation:

The triangle in question is a right angled triangle since one of the angles given is a right angle (90°)

KL is the base of the triangle which serves as the opposite of the triangle since it is facing the opposite side of the angle J.

Given angel J = 27°

If KL = 34

JL will be the hypotenuse which is the longest side of the triangle = x

Using the trigonometry identities, SOH CAH TOA

Sin(theta) = Opposite/Hypotenuse

Where theta = angle J = 27°

Opposite = 34

Sin27° = 34/Hypotenuse

Hypotenuse = 34/sin27°

Hypotenuse = 74.8