I need help guys. please help me idk it

Mathematics

1 answer:

vlada-n [284]3 years ago

4 0

Solving inequalities is almost the same as solving equalities for basic cases. Only thing you've to watch out for is signs.
For example, in 2x + 3 > 5,
We may subtract 3 from both sides,
2x > 2
Hence, by dividing both sides by 2, we get x>1.

The inequality sign changes on multiplying with (-)
For example, 2 < 6
But, -2 > -6

And when you interchange a fraction
E.g. 3/4 > 2/3
But, 4/3 < 3/2

You can now solve these of your own
Try yourself

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Can someone please help me with these 2 problems. With work please & thank u

Triss [41]

Answer:

I'm not good with the type of math on 3, so I'm going to answer 4. (P.S I don't know the question you're asking, so I'm going to assume you want to know the area and perimeter of the shapes.

Step-by-step explanation:

To solve number 4 I added the width of the 2 triangles to give me the width of the rectangle, so then 2 times 9 is 18. Then for the triangles. The formula for triangles is base times height divided by 2. So we add the areas of all shapes and we get: 18+6+24=48m. So the area for number 4 is 48 meters.

(hope this was your question)

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2 years ago

Find the point, M, that divides segment AB into a ratio of 2:3 if A is at (0.15) and B is at (20.0)

timama [110]

Answer:

M = (8,9)

Step-by-step explanation:

Notice that the points (0,15), and (20,0) form with the origin of coordinates (0,0), a right angle triangle (please see attached image). This triangle has twon perpendicular sides of length 15 and 20 respectively. Therefore, we can find the length of the segment that joins points A (0,15) and B (20,0) by finding the length of the hypotenuse in a right angle triangle (with the Pythagorean Theorem):

$AB=\sqrt{15^2+20^2} =\sqrt{625} =25$

Now, to get a 2:3 proportion on Segment AB which is of length 25, we need to divide it in five equal parts (see the picture on the right of the attached image), and place point M at two of these divisions from point A (0,15) and along segment AB.

In order to find the appropriate location in (x,y) coordinates, we consider a smaller triangle (pictured in orange in the image) that is similar to the first larger triangle (pictured in blue). Notice that if the length of AB is 25, each of its five equal divisions would be of length "5", and therefore two of them will render a length of "10" (which is the hypotenuse of this smaller right angle triangle.

Now, in order to find the sides of this smaller triangle (which can give us the clues on the horizontal and vertical coordinates of point M), we can use proportions.

To find the length "x" of the horizontal side , we do:

$\frac{x}{10} =\frac{20}{25} \\x=\frac{10*20}{25} \\x=8$

To find the length "y" of the vertical side , we do:

$\frac{y}{10} =\frac{15}{25} \\y=\frac{10*15}{25} \\y=6$

Then, the coordinate "x" of point M will be "8", while we can calculate the y position of point M subtracting "6" from 15 (the length of the vertical side in the original triangle). This gives us the coordinates (8,9) for point M as marked in orange in the picture.

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3 years ago

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