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Brrunno [24]
3 years ago
7

I need help guys. please help me idk it

Mathematics
1 answer:
vlada-n [284]3 years ago
4 0
Solving inequalities is almost the same as solving equalities for basic cases. Only thing you've to watch out for is signs.
For example, in 2x + 3 > 5,
We may subtract 3 from both sides,
2x > 2
Hence, by dividing both sides by 2, we get x>1.

The inequality sign changes on multiplying with (-)
For example, 2 < 6
But, -2 > -6

And when you interchange a fraction
E.g. 3/4 > 2/3
But, 4/3 < 3/2

You can now solve these of your own
Try yourself
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Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

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Describe the possible values for x and y when ∣x − y ∣ &gt; 0. What does it mean when ∣x − y ∣ = 0? Can ∣x − y ∣ &lt; 0? Explain
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Hope that this helped!
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