Answer:
a. P= 0.6364
b. P = 0.3636
c. Q = $21.25
d. P = 0.5
Step-by-step explanation:
given data
value of a stock varies = $13 to $24
solution
P (stock value is more than $17)
P =
P =
P = 0.6364
and
P (value of the stock is between $17 and $21)
P =
P =
P = 0.3636
and
Let the upper quartile be Q
(24 - Q) = 2.75
so
Q = $21.25
and
P(X > 20 | X > 16)
P =
P =
P = 0.5
Answer: https://mathsolver.microsoft.com/en/solve-problem/2x+4y-8=0
Step-by-step explanation: you should find your answer there
Answer:
Average speed is 37.35 mi/h
Step-by-step explanation:
given data
leave = 34 minutes before
church distance = 12.0 miles
average speed first 17 minutes = 5.0 mi/h
solution
so we find Total distance travel in first 17 minutes = speed × time
Total distance travel in first 17 minutes = 5 ×
Total distance travel in first 17 minutes = 1.416 mi
and
Distance Remaining = 12 - 1.416 = 10.584 mi
Time Remaining = 34 - 17 min = 17 min
so
remaining distance Average speed =
Average speed =
Average speed is 37.35 mi/h
The point is not know I can’t tell u
Answer:
a) $50,880
b) $48
c) 1060
Step-by-step explanation:
a)
-320x^2 + 1920x + 48000 = 0
This is a parabola that opens downward. It has a maximum value. The maximum value occurs at x = -b/(2a)
x = -b/(2a) = (-1920)/(2(-320)) = 1920/640 = 3
The maximum revenue, y, is the value of the function evaluated at x = 3.
f(x) = -320x^2 + 1920x + 48000
f(-3) = -320(3)^2 + 1920(3) + 48000
f(-3) = 50,880
The maximum revenue is $50,880
b)
Since maximum revenue occurs at x = 3, and since x represents the number of $4 discounts, the discount is 3 * $4 = $12. The price is $60 - $12 = $48
c)
$50,880/$48 = 1060