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Basile [38]
3 years ago
9

The infinite geometric sum formula can be used to write 0.126126126...as a fraction. What is the numerator of this reduced fract

ion?
A. 7
B.14
C.42
D.126
Mathematics
1 answer:
Allisa [31]3 years ago
8 0

Answer:

  • B.14

Step-by-step explanation:

0.126126126... = x

  • 1000x = 126.126126...
  • 1000x - x = 126
  • 999x = 126
  • x = 126/999= 42/333= 14/ 111

Numerator is 14

Correct answer is B.14

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5^2=25 5x5

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(-5)^2=25 -5*-5

-5^2=-25 -(5*5)

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Solve for X
ss7ja [257]

The value of x is

1. x= -37/48

2. x=0

3. x = 33/4

4.  x= -20/7

<h3>What is equation?</h3>

A mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value.

1.  6(8 x + 6) + = - 1

   48x + 36 = -1

 x= -37/48

2.  9x/7 + 6 = 6

9x/7= 6-6

9x/7 =0

x= 0*7/9

x= 0

3. 2x/11 (11 - 7) = 6

    x * 4= 6*11/2

    4x= 33

    x = 33/4

4. 11x/4 (4 - 2) = 9x + 10

 11x/4 * 2 = 9x +10

11/2*x = 9x +10

-7/2x = 10

x= -20/7

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2 years ago
1.9% as a decimal it’s for math class
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0.019

Step-by-step explanation:

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Skipping Lunch A nutritionist wishes to determine, within 3%, the true proportion of adults who do not eat any lunch. If he wish
mixas84 [53]

Answer:

A sample of at least 545 adults is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = 0.15

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.  

If he wishes to be 95% confident that his estimate contains the population proportion, how large a sample will be necessary?

We need a sample of at least n.

n is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.15*0.85}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.15*0.85}

\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.03}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.03})^{2}

n = 544.23

Rounding up

A sample of at least 545 adults is needed.

6 0
3 years ago
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