1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
posledela
3 years ago
13

What is the median of 79,85,86,90,92,93

Mathematics
1 answer:
o-na [289]3 years ago
7 0
THE MEDIAN IS THE MIDDLE NUMBER IS 86 AND 90 
You might be interested in
Write in simplest form 3m⋅4⋅n⋅n<br><br><br>​
Sedbober [7]

Hello from MrBillDoesMath!

Answer:

12 m n^2

Discussion:

3m * 4 * n * n  =                       => 3* 4 = 12

12 m * n * n                              => as n*n = n^2

12 m n^2

Thank you,

MrB

7 0
3 years ago
Read 2 more answers
A cold drink is poured out at 52°F. After 2 minutes of sitting in a 72°F room, its temperature has risen to 55°F. Find an equati
I am Lyosha [343]

Answer:

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

Step-by-step explanation:

For a cold drink in a hotter room, we can say that the rate of change of temperature of the drink is proportional to the difference of temperature between the drink and the room.

We can model that in this way

\frac{dT}{dt}=k*(T_r-T)

If we rearrange and integrate

\int\frac{dT}{(T-Tr)} =-k*\int dt\\\\ln(T-T_r)=-kt+C1\\\\T-T_r=Ce^{-kt}\\\\T=T_r+Ce^{-kt}

We know that at time 0, the temperature of the drink was 52°F. Then we have:

T=T_r+Ce^{-kt}\\\\52=72+Ce^0=72+C\\\\C=-20

We also know that at t=2, T=55°F

T=T_r+Ce^{-kt}\\\\55=72-20e^{-k*2}\\\\e^{-k*2}=(72-55)/20=0.85\\\\-2k=ln(0.85)=-0.1625\\\\k=0.08

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

7 0
3 years ago
HELP PELASE!!!!!!!! THESE ARE DUE SOON and a grade
likoan [24]
Answer: 6,400 Explanation: there is 3200 ounces in one ton so i took that and divided it by 5
3 0
3 years ago
Read 2 more answers
MATH: GRAPHS AND FUNCTIONS 3. HELP! 12 PTS (HARD)
JulijaS [17]

Answer:

Step-by-step explanation:

4 0
2 years ago
While bowling with friends, Brandy rolls a strike in 57 out of 72 frames. what is the experimental probability that brandy will
gogolik [260]

Answer:

79.17% probability that brandy will roll a strike the first frame of the next game

Step-by-step explanation:

The experimental probability is the probability based on previous outcomes, that is, the number of desired outcomes divided by the number of total outcomes.

While bowling with friends, Brandy rolls a strike in 57 out of 72 frames. What is the experimental probability that brandy will roll a strike the first frame of the next game?  

Desired outcomes:

57 strikes

Total outcomes:

72 frames

Probability:

p = 57/72 = 0.7917

79.17% probability that brandy will roll a strike the first frame of the next game

3 0
3 years ago
Other questions:
  • A student has some 1 bills and $5 bills in his wallet. he has a total of 15 bills that are worth $47. how many of each type of b
    6·2 answers
  • Diego parakeet is 13 centimeters,4 millimeters tall how tall is his parakeet in millimeters
    5·1 answer
  • The half-life of the radioactive elements unobtanium -41 is 5 seconds. If 48 grams of unobtanium -41 are initially present, how
    5·1 answer
  • Salma is saving money to buy a game. So far she has saved
    7·2 answers
  • On a certain day in Alaska, the probability of low seismic activity for the next 24 hours was reported to be about 1%. Use this
    10·1 answer
  • Evaluate the expression: 2 ⋅ 6^2
    11·2 answers
  • if a plane can travel 480 miles per hour with the wind and 400 miles per hour against the wind, find the speed of the wind and t
    5·1 answer
  • The manager of a shopping center wishes to obtain information on the shopping habits of people in the area. The area
    14·1 answer
  • Use a trigonometric function to find each value of x. Round to the nearest tenth if necessary.
    10·1 answer
  • I need the answer in the next 6 hours
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!