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3 years ago

JUIVING a Percentage PION

Mathematics

1 answer:

Fed [463]3 years ago

3 0

Answer:

the bike is $65

Step-by-step explanation:

$50 and 15 percent more

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What is the length of the side labeled x cm?

UkoKoshka [18]

When we know 2 angles and one side, we use the Law of Sines.
First we need to find that third angle.
Angle A =
180 -41 -62 = 77 degrees

The Law of Sines states that

side a / Sine (A) = side x / Sine (X)
14 / Sine (77) = side x / Sine (41)

14 * Sine (41) / Sine (77) = side x

side x = 14 * 0.65606 / 0.97437
side x = 9.18484 / 0.97437

 side x = 9.4264396482

5 0

3 years ago

Write the equation for this line

Nimfa-mama [501]

Answer:

y = 4x + 3

Step-by-step explanation:

7 0

3 years ago

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0

3 years ago

Select all ordered pairs that correspond to input-output pairs of the function y = −7x + 6.

horrorfan [7]

Answer:

There are no options, so i will answer in a general way.

In a function:

y = f(x)

The output is y, and the input is x, and the ordered pair is written as (x, y)

In this case, we have the function:

y = -7*x + 6

Then we need to have different inputs and then find the outputs for each.

For example, if x = 1.

y = -7*1 + 6 = -1

Then we have the ordered pair (1, - 1)

if x = 0

y = -7*0 + 6 = 6

then we have the ordered pair (0, 6)

The general ordered pair is written as:

(x, y = -7*x + 6)

or:

(x, -7*x + 6)

Where you only need to replace the value of x.

8 0

3 years ago

Somebody help me with this

zubka84 [21]

Answer:

Step-by-step explanation:

when multiplying fractions it doesn’t matter if they have the same denominator (bottom) just multiply straight across

(6/12)x(6/3)

36/36

4 0

3 years ago