The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. Which the following equation
s could be used to find the smaller integer,n?
1 answer:
Answer:
n+(n+2)+20=4n
Step-by-step explanation:
Let the smaller integer be n,
the bigger odd integer will be n+2.
n+(n+2)+20=4n
2n+22=4n
2n=22
n=11
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