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ICE Princess25 [194]

3 years ago

7

The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. Which the following equation

s could be used to find the smaller integer,n?

1 answer:

PSYCHO15rus [73]3 years ago

6 0

Answer:

n+(n+2)+20=4n

Step-by-step explanation:

Let the smaller integer be n,

the bigger odd integer will be n+2.

n+(n+2)+20=4n

2n+22=4n

2n=22

n=11

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Find the values of the apple, banana and lollypop below.<br><br> Pls help

maks197457 [2]

Answer:

a= Apple = 3

b= Banana =5

v= Lollypop=1

Step-by-step explanation:

36 is divided into 2 giving us 18

Let apple=a

Banana=b

Lollypop=c

In the first half

An apple + 3 bananas=18

a+3b=18 (1)

Second half is further divided into 2

That is,

18÷2=9

First half of the second half

3apples=9

3a=9 (2)

Second half of the second half

1 apple + 1 banana + 1 lollypop=9

a+b+c=9 (3)

a+3b=18 (1)

3a=9 (2)

a+b+c=9 (3)

From (2)

3a=9

Divide both sides by 3

a=9/3

a=3

Substitute a=3 into 1

a+3b=18

3+3b=18

3b=18-3

3b=15

Divide both sides by 3

b=15/3

=5

b=5

Substitute the value of a and b into (3)

a+b+c=9

3+5+c=9

8+c=9

c=9-8

c=1

Therefore,

a= Apple = 3

b= Banana =5

v= Lollypop=1

6 0

4 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

3 years ago

I found something funny

Finger [1]

Answer:

yesssssssssssss

Step-by-step explanation:

FLIP ALL THE TABLESSSSSSSSS

6 0

3 years ago

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How do you write 47.15 in expanded form?

Helga [31]

40+7+0.1+0.05 this is the answer i think

5 0

3 years ago

Find the number of sides of a regular polygon if the measure interior angle is 160°

MrMuchimi

360/20 is equal to 18 sides

6 0

3 years ago