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Elden [556K]
3 years ago
8

What is the answer to the expression “ 13! “

Mathematics
1 answer:
earnstyle [38]3 years ago
5 0

13!=13×12×11×10×9×8×7×6×5×4×3×2×1

=6,227,020,800

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Consider all four-digit numbers that can be made from the digits 0-8 (assume that numbers cannot start with 0). What is the prob
vodomira [7]

Answer:

0.2498

Step-by-step explanation:

Number of 4 digit numbers that can be formed from the digit (0 - 8), assume number can't start from 0

Thus ;

First digit = (1, 2, 3, 4, 5, 6, 7, 8) = 8 ways

Next three digits = (0, 1, 2, 3, 4, 5, 6, 7, 8) = 9 ways

Hence,

Total possible outcomes = sample space = (8 * 9 * 9 * 9) = (8 * 9^3 ) = 8 * 729 = 5832

Required = number greater Than 7000

For number to be greater Than 7000, starting digit should be either 7 or 8

Hence,

First digit = 2 ways

Next three digits = 9 ways

Also excluding 7000

Hence, Number of digits above 7000;

2 * 9^3 = 2 * 729 = 1458 - 1 = 1457

Hence,

Probability = 1457 / 5832

= 0.2498285

= 0.2498

7 0
3 years ago
Can someone help me with this?
baherus [9]

Answer:

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Step-by-step explanation:

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But AW also equals WB because of the bisecting point

x + 6 = 3x

6 = 2x

x = 3

AW = 3 + 6 = 9

WB = 3(3) = 9

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If my answer is incorrect, pls correct me!

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I am a factor of 32. The other factor is 4 . What number am i
julsineya [31]
The other number is 8 because 8 x 4 = 32
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Answer:

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Step-by-step explanation:

3 \times 2 \times 3

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