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strojnjashka [21]
3 years ago
10

Solve each equation. Check your solutions. 5 - 3|2 + 2w|= -7

Mathematics
2 answers:
Trava [24]3 years ago
8 0
5-3(2+2w)=-7
5-6-6w=-7
-6w=-7-5+6
-6w=-6
w=1
Citrus2011 [14]3 years ago
7 0

Answer:

w=1\text{ or } w=-3

Step-by-step explanation:

So we have the equation:

5-3|2+2w|=-7

First, subtract 5 from both sides:

-3|2+2w|=-12

Divide both sides by -3:

|2+2w|=4

Definition of Absolute Value:

2+2w=4\text{ or } 2+2w=-4

Divide both sides of the equation by 2 for both equations:

1+w=2\text{ or } 1+w=-2

Subtract 1 from both sides:

w=1\text{ or } w=-3

And we're done!

To check:

5-3|2+2(1)|=-7

Multiply:

5-3|2+2|=-7

Add:

5-3|4|=-7

Multiply:

5-12=-7

Subtract:

-7\stackrel{\checkmark}{=}-7

And:

5-3|2+2(-3)|=-7

Multiply:

5-3|2-6|=-7

Subtract:

5-3|-4|=-7

Absolute Value:

5-3(4)=-7

Multiply:

5-12=-7

Subtract:

-7\stackrel{\checkmark}{=}-7

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<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>

<u>x =  \frac{ - 6 + 3y}{2}</u>

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<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>

<u>2y - 3 =  \frac{ - 6 + 3y}{2}</u>

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

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