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strojnjashka [21]
4 years ago
10

Solve each equation. Check your solutions. 5 - 3|2 + 2w|= -7

Mathematics
2 answers:
Trava [24]4 years ago
8 0
5-3(2+2w)=-7
5-6-6w=-7
-6w=-7-5+6
-6w=-6
w=1
Citrus2011 [14]4 years ago
7 0

Answer:

w=1\text{ or } w=-3

Step-by-step explanation:

So we have the equation:

5-3|2+2w|=-7

First, subtract 5 from both sides:

-3|2+2w|=-12

Divide both sides by -3:

|2+2w|=4

Definition of Absolute Value:

2+2w=4\text{ or } 2+2w=-4

Divide both sides of the equation by 2 for both equations:

1+w=2\text{ or } 1+w=-2

Subtract 1 from both sides:

w=1\text{ or } w=-3

And we're done!

To check:

5-3|2+2(1)|=-7

Multiply:

5-3|2+2|=-7

Add:

5-3|4|=-7

Multiply:

5-12=-7

Subtract:

-7\stackrel{\checkmark}{=}-7

And:

5-3|2+2(-3)|=-7

Multiply:

5-3|2-6|=-7

Subtract:

5-3|-4|=-7

Absolute Value:

5-3(4)=-7

Multiply:

5-12=-7

Subtract:

-7\stackrel{\checkmark}{=}-7

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If an instrument measures in units of 10, then any value between which two values would be measured as 80?
enyata [817]

Answer:

The answer is 75 and 85.

Step-by-step explanation:

If the instrument measures in units of 10, then the measurement could be 5 units on either side of 80 (80 − 5 = 75, 80 + 5 = 85). Any value between 75 and 85 would be measured as 80.

4 0
3 years ago
Question is the attached file.
Gwar [14]

Answer:

The critical points are 12 and 0.

Step-by-step explanation:

We have that the critical numbers are those values that result from equating the derivative of a function to zero. Also called roots or zeros of the derived function.

IF f is defined in x, it will be said that a is a critical number of f if f '(x) = 0 or if f is not defined in x.

Now the function is:

f (x) = x ^ 2 / (x -6)

we have that the derivative of the quotient is:

(f / g) '= (f' * g - g '* f) / g ^ 2

we replace and we have:

f (x) = [2 * x * (x-6) - 1 * x ^ 2] / (x -6) ^ 2

simplifying we have:

f (x) = [x ^ 2 - 12 * x] / (x -6) ^ 2

this must be equal to 0, like this:

 [x ^ 2 - 12 * x] / (x -6) ^ 2 = 0

we solve:

x ^ 2 - 12 * x = 0

x * (x - 12) = 0

Thus:

x = 0

x - 12 = 0 => x = 12

The critical points are 12 and 0.

6 0
3 years ago
3t(t+2)-3t^2 for t=19
nekit [7.7K]

Good evening Gloria

3t(t+2)-3t² for t=19

Well the first thing we need to do is to replace 19 everywhere we see T

So let's do it together

3(19)(19+2)-3(19)²

57(21)-3(361)

1197-1083

= 114

I hope that's help and if you have questions please let me know :)


Please give my answer a Thanks and stars ↓

8 0
3 years ago
Please help me i have 1 more after this
Zinaida [17]

Answer:

11

Step-by-step explanation:

24 -:- 3+3

8+3

11

7 0
3 years ago
Read 2 more answers
Can someone help me?
Vesnalui [34]

Step-by-step explanation:

1. 1/13 2. 1/26

4 0
3 years ago
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