Answer:
PQ and QR are congruent.
Step-by-step explanation:
The length of PQ = sqrt [(2 - -1)^2 + (-1 - 3)^2]
= sqrt 25
= 5 units.
QR = sqrt [(5-2)^2 + (3 - -1)^2) ]
= sqrt 25
= 5 units.
PR = sqrt [ ( 3-3^2 + (5- -1)^2]
= sqrt 36
= 6 units.
Answer:
1458 sq cm
Step-by-step explanation:
because each dimension of A is 3 tomes each dimension of B, that will mean that both the length and width of B are multiplied by 3 in order to get the length and width of A, so the area of B is length×width=162 and the area of A (in terms of B's dimensions) is 3xlength×3×width=9×length×width=9×162=1458 sq cm
Unfortunately, you inadvertently cut off the instructions for this problem when you photographed it. Could you try again, making certain to include the instructions?
Let me guess: perhaps the instructions are 1) determine the slope of the line passing through the given points, or 2) write the equation of the line passing through the given points.
Answer:
9 represents the initial height from which the ball was dropped
Step-by-step explanation:
Bouncing of a ball can be expressed by a Geometric Progression. The function for the given scenario is:
The general formula for the geometric progression modelling this scenario is:
Here,
represents the initial height i.e. the height from which the object was dropped.
r represents the percentage the object covers with respect to the previous bounce.
Comparing the given scenario with general equation, we can write:
= 9
r = 0.7 = 70%
i.e. the ball was dropped from the height of 9 feet initially and it bounces back to 70% of its previous height every time.
for the first one set 3y+y=180 and y+x=180
the second one set w+y=180, 42+x=180, y+20=180, and 87+v
