Answer:
Step-by-step explanation:
Confidence interval for the difference in the two proportions is written as
Difference in sample proportions ± margin of error
Sample proportion, p= x/n
Where x = number of success
n = number of samples
For the men,
x = 318
n1 = 520
p1 = 318/520 = 0.61
For the women
x = 379
n2 = 460
p2 = 379/460 = 0.82
Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]
To determine the z score, we subtract the confidence level from 100% to get α
α = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025
This is the area in each tail. Since we want the area in the middle, it becomes
1 - 0.025 = 0.975
The z score corresponding to the area on the z table is 1.96. Thus, confidence level of 95% is 1.96
Margin of error = 1.96 × √[0.61(1 - 0.61)/520 + 0.82(1 - 0.82)/460]
= 1.96 × √0.0004575 + 0.00032086957)
= 0.055
Confidence interval = 0.61 - 0.82 ± 0.055
= - 0.21 ± 0.055
538
-247
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8-7=1
Cross out 5 and make it 4. Make 3 into 13. 13-4=9
4-2=2
The answer is: 291
Answer:
YEET
Step-by-step explanation:
Whatever y is multiply it my 12, because there are 12 months in a year.
Most times, it’s good to talk to your teacher for help. I think it would be a good idea to ask your parent, sibling or any adult for help. Sometimes you think harder than you should so relax and try reading the question again. I hope you figure this out! Good luck!
First, turn 70% into a decimal by dividing 70 by 100.
70% ⇒ 0.70
Multiply 120 by 0.70.
120 × 0.70 = 84
Now we know that 84 students are involved in extracurricular activities. Subtract 84 from 120 to find the amount of students who are <em>not</em> involved in extracurricular activities.
120 - 84 = 36
<h2>Answer:</h2>
<u>36 seventh grade students are not involved in extracurricular activities.</u>
