Answer:
7
Step-by-step explanation:
Everything including 1/2 and above rounds up to the next whole number.
3/8 < 4/8
7 and 3/8 rounds to 7
Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
70 miles /hour = r
Step-by-step explanation:
d=rt
Substitute d=350 miles and t = 5 hours
350 miles = r* 5 hours
Divide each side by 5 hours
350 miles = 5 hours = r
70 miles /hour = r
Answer:
a. We get 56 heads out of 100 tosses.
We will use one sample proportion test
x = 56
n = 100
Formula of test statistic =
=
=
refer the z table for p value
p value = 0.8849
a. We get 560 heads out of 1000 tosses.
We will use one sample proportion test
x = 560
n = 1000
Formula of test statistic =
=
=
refer the z table for p value
p value = .000148
p value of part B is less than Part A because part B have 10 times the number the tosses.
