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kifflom [539]
3 years ago
8

Find the approximate volume of a cone with radius 10 inches and a vertical height of 24 inches. ANSWERS: 414,565 in3 2,513 in3 6

,529 in3 740 in3
Mathematics
1 answer:
OLEGan [10]3 years ago
7 0

Answer:2,513in3

Step-by-step explanation:

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Round 7 3/8 to the nearest whole number?!?
DIA [1.3K]

Answer:

7

Step-by-step explanation:

Everything including 1/2 and above rounds up to the next whole number.

3/8 < 4/8

7 and 3/8 rounds to 7

5 0
3 years ago
A luxury liner leaves a port on a bearing of 110 degrees and travels 8.8 miles. It then turns due west and travels 2.4 miles. Ho
myrzilka [38]

Answer:

Distance= 6.6 miles

Bearing= N 62.854°W

Step-by-step explanation:

Let's determine angle b first

Angle b=20° (alternate angles)

Using cosine rule

Let the distance between the liner and the port be x

X² =8.8²+2.4²-2(8.8)(2.4)cos20

X²= 77.44 + 5.76-(39.69)

X²= 43.51

X= √43.51

X= 6.596

X= 6.6 miles

Let's determine the angles within the triangle using sine rule

2.4/sin b = 6.6/sin20

(2.4*sin20)/6.6= sin b

0.1244 = sin b

7.146= b°

Angle c= 180-20-7.146

Angle c= 152.854°

For the bearing

110+7.146= 117.146

180-117.146= 62.854°

Bearing= N 62.854°W

8 0
3 years ago
in a recent semester at a local university 520 students enrolled in both general chemistry and calculus 1. Of these students 88
IceJOKER [234]

Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that

P(Ch) = 88/520

P(C) = 76/520

P(Ch and C) = 31/520

and we want to find P(Ch or C).

Using the inclusion/exclusion principle, we have

P(Ch or C) = P(Ch) + P(C) - P(Ch and C)

P(Ch or C) = 88/520 + 76/520 - 31/520

P(Ch or C) = 133/520

6 0
3 years ago
Using d= rt, find r if d= 350 miles and t= 5 hours
lubasha [3.4K]

Answer:

70 miles /hour = r

Step-by-step explanation:

d=rt

Substitute d=350 miles and t = 5 hours

350 miles = r* 5 hours

Divide each side by 5 hours

350 miles = 5 hours = r

70 miles /hour = r

3 0
2 years ago
Suppose that we are testing a coin to see if it is fair, so our hypotheses are: H0: p = 0.5 vs Ha: p ≠ 0.5. In each of (a) and (
aleksley [76]

Answer:

H_0: p = 0.5\\H_a: p \neq 0.5

a. We get 56 heads out of 100 tosses.

We will use one sample proportion test  

x = 56

n = 100

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{56}{100}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}

                                       =1.2

refer the z table for p value

p value = 0.8849

a.  We get 560 heads out of 1000 tosses.

We will use one sample proportion test  

x = 560

n = 1000

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{560}{1000}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}

                                       =3.794

refer the z table for p value

p value = .000148

p value of part B is less than Part A because part B have 10 times the number the tosses.

6 0
3 years ago
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