The composite function combines the palm tree and the seed functions
The composite function is t(d) = 60d + 20
<h3>How to determine the composite functions</h3>
The functions are given as:
Number of palm trees: t(s) = 3s + 20
Number of seeds: s(d) = 20d
The composite function that represents the number of palm trees Carlos can expect to grow over a certain number of days is represented as:
t(s(d))
This is calculated as:
t(s(d)) = 3s(d) + 20
Substitute s(d) = 20d
t(s(d)) = 3 * 20d + 20
Evaluate the product
t(s(d)) = 60d + 20
Rewrite as:
t(d) = 60d + 20
Hence, the composite function is t(d) = 60d + 20
Read more about composite functions at:
brainly.com/question/10687170
Remember that you can always multiply or divide BOTH the numerator and denominator
of the fraction by anything you want to. You just have to do exactly the same to both of
them.
The way to simplify a fraction is to divide both the numerator and denominator by their
greatest common factor.
Do you see all of those 'x's on the top and bottom ? The top and bottom can
both be divided by x-cubed.
<u>Numerator:</u>
Divide (-4³) by x³, and you have (-4) left.
<u>Denominator:</u>
Divide (x³ - 2x⁴) by x³, and you have (1 - 2x) left.
So, the simplified fraction is [ -4 / (1 - 2x) ].
That's a perfectly good answer, but you could make it look a little prettier
if you multiply the top and bottom both by -1 . Then it would be
4 / (2x - 1) .
Either one is fine.
Answer:
all real numbers
Step-by-step explanation:
simplify each side of the inequality
26 + 6b -- already fully simplified
2(3b + 4) → 6b + 8
26 + 6b ≥ 6b + 8
subtract 6b from both sides
26 ≥ 8
since this expression is true (26 is greater than 8), then the solution is all real numbers. any value could take the place of b because in the end, it will be canceled out by itself, resulting in 26 ≥ 8
Answer:
40 5x4 20 20x2 40
Step-by-step explanation:
Answer:
The base (b) has to be positive and different of 1. The logarithm is the inverse of exponential, so:
logb(a) = x ⇒ a = bˣ
So, for b = 0 ⇒ 0ˣ = a
And there is impossible, "a" only could be 0.
For b = 1 ⇒ 1ˣ = a
And the same thing would happen, the logarithming would be to be 1, and the function will be extremally restricted.
For b<0, then the expression a = bˣ will be also restricted, and will not represent all values of a.
So, 0<b<1 and b >1.
