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2 years ago

24. Find the area of the shaded region:

Mathematics

2 answers:

Monica [59]2 years ago

7 0

Answer:

A = 5x³ + 17x² - 35x - 30

Step-by-step explanation:

the shaded area (A) is calculated as

A = outer area - inner area

= (5x + 3)(x² + 4x - 10) - 3x(2x - 1) ← distribute parenthesis

= 5x³ + 20x² - 50x + 3x² + 12x - 30 - (6x² - 3x)

= 5x³ + 23x² - 38x - 30 - 6x² + 3x ← collect like terms

= 5x³ + 17x² - 35x - 30

Fudgin [204]2 years ago

3 0

Answer:

5x^3+ 17x^2- 35x-30 Or x=-4.63 or 1.9

Step-by-step explanation:

Area of rectangle =L×B

for smaller rectangle :

after applying the formula, the equation becomes:

6x^2 - 3x

For bigger rectangle:

Applying the same formula, the equation becomes:

5x^3+ 23x^2- 38x- 30

Area of shaded region =

Area of bigger rectangle- Area of smaller rectangle

= 5x^3+17x^2 -35x-30

going further solving the above equation

Area of shaded region: -4.96 or 1.9

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4 years ago

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If Joe drives 186.83 miles on a business trip, and the reimbursement from his company is $13.08. At what rate is Joe's employer

kirill115 [55]

Answer:

7 cents/mile

Step-by-step explanation:

You are looking for a unit rate of cents per mile.

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3 years ago

Type the correct answer in each box. Use numerals instead of words.

lubasha [3.4K]

Answer:

System A has 4 real solutions.

System B has 0 real solutions.

System C has 2 real solutions

Step-by-step explanation:

System A:

x^2 + y^2 = 17 eq(1)

y = -1/2x eq(2)

Putting value of y in eq(1)

x^2 +(-1/2x)^2 = 17

x^2 + 1/4x^2 = 17

5x^2/4 -17 =0

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a = 5/4, b =0 and c = -17

$x=\frac{-(0)\pm\sqrt{(0)^2-4(5/4)(-17)}}{2(5/4)}\\x=\frac{0\pm\sqrt{85}}{5/2}\\x=\frac{\pm\sqrt{85}}{5/2}\\x=\frac{\pm2\sqrt{85}}{5}$

Finding value of y:

y = -1/2x

$y=-1/2(\frac{\pm2\sqrt{85}}{5})$

$y=\frac{\pm\sqrt{85}}{5}$

System A has 4 real solutions.

System B

y = x^2 -7x + 10 eq(1)

y = -6x + 5 eq(2)

Putting value of y of eq(2) in eq(1)

-6x + 5 = x^2 -7x + 10

=> x^2 -7x +6x +10 -5 = 0

x^2 -x +5 = 0

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b =-1 and c =5

$x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(5)}}{2(1)}\\x=\frac{1\pm\sqrt{1-20}}{2}\\x=\frac{1\pm\sqrt{-19}}{2}\\x=\frac{1\pm\sqrt{19}i}{2}$

Finding value of y:

y = -6x + 5

y = -6(\frac{1\pm\sqrt{19}i}{2})+5

Since terms containing i are complex numbers, so System B has no real solutions.

System B has 0 real solutions.

System C

y = -2x^2 + 9 eq(1)

8x - y = -17 eq(2)

Putting value of y in eq(2)

8x - (-2x^2+9) = -17

8x +2x^2-9 +17 = 0

2x^2 + 8x + 8 = 0

2x^2 +4x + 4x + 8 = 0

2x (x+2) +4 (x+2) = 0

(x+2)(2x+4) =0

x+2 = 0 and 2x + 4 =0

x = -2 and 2x = -4

x =-2 and x = -2

So, x = -2

Now, finding value of y:

8x - y = -17

8(-2) - y = -17

-16 -y = -17

-y = -17 + 16

-y = -1

y = 1

So, x= -2 and y = 1

System C has 2 real solutions

4 0

4 years ago

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Maggie has $40 to buy a new dress and hair accessory for her school dance the dress she wants cost $35.75 the cost of her hair a

jonny [76]

Answer:

Yes Maggie has enough money to purchase the dress and hair accessory.

Step-by-step explanation:

Dress = $35.75

Hair accessory = $2.80

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Does her have enough money?

Total Money in pocket - (Dress cost + hair accessory)

$40.00 - ($35.75 + 2.80)

$40.00 - ($36.00 + $3.00) Round to the nearest dollar

$40.00 - $39.00 = $1.00

Yes

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3 years ago