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DiKsa [7]
3 years ago
11

B2 - 7b + 12 = 0

Mathematics
2 answers:
olga_2 [115]3 years ago
6 0
B2-7b+12=0
(b-3)(b-4)=0
b= 3 or 4
JulijaS [17]3 years ago
3 0

Answer: (b - 4)(b - 3); b = 4 and 3

Step-by-step explanation:

ima assume these are exponents since you didnt care to correctly write the equation.

What two numbers multiply to equal 12, but add to equal -7? That's -4 and -3

So the factored form of this trinomial is (b - 4)(b - 3) = 0. Make each of these expressions equal to 0 in order to get your answer.

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Which number sentence is true? A. –7 + 10 = –3 B. –7 – (–10) = –17 C. 7 – 10 = 3 D. 7 – (–10) = 17
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<><><><><>

Answer: \boxed{\bold{7-\left(-10\right)}}

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Explanation: \downarrow\downarrow\downarrow

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What is the remainder when 16,055 is divided by 16? (Input numeric values only)
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3 years ago
What is the solution set of x2 + 5x + 1 = 0?
DerKrebs [107]

Answer:

\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}

Step-by-step explanation:

x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}

\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}

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3 years ago
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