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3 years ago

A and B are two events. Which statement about the conditional probability is true?

2 answers:

4 0

The answer
by using fundamental definition
The conditional probability of event B given event A is P(B|A)=P(A and B)/P(A) when two events are not independent.
so the only true answer is A, because P(B|A)=P(A) if A and B are independents
(definition)

Zinaida [17]3 years ago

4 0

The answer is A. I just took the quiz.

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Plz help me with this

Sonbull [250]

1) this is total area of two triangle
area of a triangle=1/2*b*h
A=1/2*9*4
A=18 inches^2
multiply by 2 because there are two triangle with same measure
2A=2*18=36 inches^2

3) this is a area of rectangle and a triangle and then subtract
A2=9.3x7.8= 72.54
area of triangle A1=1/2*7.8 *3.3=12.87
A2-A1=59.69 mm^2

5) now u ca do it

4 0

3 years ago

Please help me answer this.

adoni [48]

Answer:

See explanation

Step-by-step explanation:

Statements Reasons

1. $\overline{AD}\parallel \overline{BC}$ Given

2. $\angle ADB\cong \angle CBD$ As alternate interior angles when parallel lines AD and BC intersect by ltransversal BD

3. $\overline{AD}\cong \overline{BC}$ Given

4. $\overline{BD}\cong \overline{DB}$ Reflexive property

5. $\triangle ADB\cong \triangle CBD$ SAS postulate

6. $\angle ABD\cong \angle CDB$ Corresponding parts of congruent triangles are congruent

7. $\overline{AB}\parallel \overline{CD}$ Inverse alternate interior angles theorem

8 0

3 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

Step-by-step explanation:

Denote the events as follows:

D = Dave will show up.

M = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

3 years ago

Read 2 more answers

A pre-election survey showed that 3 out of every 5 citizens would vote in an election. At this rate, how many people would be ex

noname [10]

Answer:

9600 people would vote.

Step-by-step explanation:

3/5 = .6

16,000 * .6 = 9600

3 0

2 years ago

When 9/10 is divided by 2/5 , will the quotient be greater than 1 or less than 1.

Feliz [49]

9/10 * 5/2 = 45/20
The quotient will be greater than 1

3 0

3 years ago

Read 2 more answers