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Gekata [30.6K]
2 years ago
12

52.2 697 rounded to the nearest hundredth two decimal places​

Mathematics
2 answers:
andreev551 [17]2 years ago
6 0

Answer:

52.27

Step-by-step explanation:

Anit [1.1K]2 years ago
3 0

Answer:

52.27

Step-by-step explanation:

The 7 rounds up to 8 witch causes the 9 to round to the 7 you need in the answer, hope this helps.

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The Cool Company determines that the supply function for its basic air conditioning unit is S(p) = 40 + 0.008p3 and that its dem
myrzilka [38]

We are given the functions:

<span>S (p) = 40 + 0.008 p^3                                     ---> 1</span>

<span>D (p) = 200 – 0.16 p^2                                     ---> 2</span>

 

T o find for the price in which the price of supply equals demand, all we have to do is to equate the two equations, equation 1 and 2, and calculate for the value of p, therefore:

S (p) = D (p)

40 + 0.008 p^3 = 200 – 0.16 p^2

0.008 p^3 + 0.16 p^2 = 160

p^3 + 20 p^2 = 20,000

p^3 + 20 p^2 – 20,000 = 0

Calculating for the roots using the calculator gives us:

p = 21.86, -20.93±21.84i

 

Since price cannot be imaginary therefore:

p = 21.86

3 0
3 years ago
$22.85 for Shiping 3 pound package
Ymorist [56]

Answer:

Step-by-step explanation:BASE+3X=22.85

BASE+10X=40

BASE=40-10X NOW SUBSTITUTE (40-10X)FOR BASE IN THE FIRST EQUATION

40-10X+3X=22.85

-7X=22.85-40

-7X=-17.15

X=-17.15/-7

X=$2.45 IS THE PRICE FOR EACH POUND.

BASE+10*2.45=40

BASE+24.50=40

BASE=40-24.50

BASE=15.50 IS THE BASE PRICE FOR THE DELIVERY.

PROOF

15.50+3*2.45=22.85

15.50+7.35=22.85

22.85=22.85

3 0
2 years ago
Solve the equation 4(x+2)-17=35
Lostsunrise [7]
X=11 I say .......... ...
3 0
3 years ago
Read 2 more answers
Use Gaussian elimination to write each system in triangular form
Feliz [49]

Answer:

To see the steps to the diagonal form see the step-by-step explanation. The solution to the system is x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

Step-by-step explanation:

Gauss elimination method consists in reducing the matrix to a upper triangular one by using three different types of row operations (this is why the method is also called row reduction method). The three elementary row operations are:

  1. Swapping two rows
  2. Multiplying a row by a nonzero number
  3. Adding a multiple of one row to another row

To solve the system using the Gauss elimination method we need to write the augmented matrix of the system. For the given system, this matrix is:

\left[\begin{array}{cccc|c}1 & 1 & 1 & 1 & 1 \\1 & 1 & 0 & -1 & -1 \\-1 & 1 & 1 & 2 & 2 \\1 & 2 & -1 & 1 & 0\end{array}\right]

For this matrix we need to perform the following row operations:

  • R_2 - 1 R_1 \rightarrow R_2 (multiply 1 row by 1 and subtract it from 2 row)
  • R_3 + 1 R_1 \rightarrow R_3 (multiply 1 row by 1 and add it to 3 row)
  • R_4 - 1 R_1 \rightarrow R_4 (multiply 1 row by 1 and subtract it from 4 row)
  • R_2 \leftrightarrow R_3 (interchange the 2 and 3 rows)
  • R_2 / 2 \rightarrow R_2 (divide the 2 row by 2)
  • R_1 - 1 R_2 \rightarrow R_1 (multiply 2 row by 1 and subtract it from 1 row)
  • R_4 - 1 R_2 \rightarrow R_4 (multiply 2 row by 1 and subtract it from 4 row)
  • R_3 \cdot ( -1) \rightarrow R_3 (multiply the 3 row by -1)
  • R_2 - 1 R_3 \rightarrow R_2 (multiply 3 row by 1 and subtract it from 2 row)
  • R_4 + 3 R_3 \rightarrow R_4 (multiply 3 row by 3 and add it to 4 row)
  • R_4 / 4.5 \rightarrow R_4 (divide the 4 row by 4.5)

After this step, the system has an upper triangular form

The triangular matrix looks like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & -0.5 & -0.5  \\0 & 1 & 0 & -0.5 & -0.5\\0 & 0 & 1 & 2 &  2 \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

If you later perform the following operations you can find the solution to the system.

  • R_1 + 0.5 R_4 \rightarrow R_1 (multiply 4 row by 0.5 and add it to 1 row)
  • R_2 + 0.5 R_4 \rightarrow R_2 (multiply 4 row by 0.5 and add it to 2 row)
  • R_3 - 2 R_4 \rightarrow R_3(multiply 4 row by 2 and subtract it from 3 row)

After this operations, the matrix should look like:

\left[\begin{array}{cccc|c}1 & 0 & 0 & 0 & -\frac{1}{9}  \\0 & 1 & 0 & 0 &   -\frac{1}{9}\\0 & 0 & 1 & 0 &  \frac{4}{9} \\0 & 0 & 0 & 1 &  \frac{7}{9}\end{array}\right]

Thus, the solution is:

x =  -\frac{1}{9}, y= -\frac{1}{9}, z= \frac{4}{9} and w = \frac{7}{9}

7 0
3 years ago
Cosxsinx-2cosx=0<br> I dont know how to solve this
jekas [21]
Factor out cosx: cosx(sinx-2)=0
cosx=0 or sinx-2=0
cosx=0 or sinx=2
the largest value of sinx is 1, sinx will never be 2, so cosx=0, x=π/2 or 3π/2 are the two answers. 
8 0
3 years ago
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