We are given the functions:
<span>S (p) = 40 + 0.008 p^3 --->
1</span>
<span>D (p) = 200 – 0.16 p^2 --->
2</span>
T o find for the price in which the price of supply equals
demand, all we have to do is to equate the two equations, equation 1 and 2, and
calculate for the value of p, therefore:
S (p) = D (p)
40 + 0.008 p^3 = 200 – 0.16 p^2
0.008 p^3 + 0.16 p^2 = 160
p^3 + 20 p^2 = 20,000
p^3 + 20 p^2 – 20,000 = 0
Calculating for the roots using the calculator gives us:
p = 21.86, -20.93±21.84i
Since price cannot be imaginary therefore:
p = 21.86
Answer:
Step-by-step explanation:BASE+3X=22.85
BASE+10X=40
BASE=40-10X NOW SUBSTITUTE (40-10X)FOR BASE IN THE FIRST EQUATION
40-10X+3X=22.85
-7X=22.85-40
-7X=-17.15
X=-17.15/-7
X=$2.45 IS THE PRICE FOR EACH POUND.
BASE+10*2.45=40
BASE+24.50=40
BASE=40-24.50
BASE=15.50 IS THE BASE PRICE FOR THE DELIVERY.
PROOF
15.50+3*2.45=22.85
15.50+7.35=22.85
22.85=22.85
X=11 I say .......... ...
Factor out cosx: cosx(sinx-2)=0
cosx=0 or sinx-2=0
cosx=0 or sinx=2
the largest value of sinx is 1, sinx will never be 2, so cosx=0, x=π/2 or 3π/2 are the two answers.