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3 years ago

Choose an angle or point from the preimage and name its image

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

4 0

From the preimage, the angle or point I choose is P and I name its image as: P maps to P’.

The set of all elements of the domain that map to the members of S is the inverse image or preimage of a particular subset S of the codomain of a function.

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PLEASE HELP!!!

Svetradugi [14.3K]

B or c for the equation because it is 1-n

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4 years ago

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Help pls for 100 points!!!

Rus_ich [418]

Answer:

$x\leq 9$

Step-by-step explanation:

Subtract 7 From both sides

$x+7-7\le \:16-7$

7-7 = 0, 16 - 7=9

That leaves $x \leq 9$

Hope this helps

~R3V0

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3 years ago

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What is the standard form of the equation of a circle whose diameter is 20 units and whose center is (−1,7)?

VARVARA [1.3K]

Answer:

$(x + 1)^2 + (y - 7)^2 = 100$

Step-by-sep explanation:

Given:

Diameter of circle = 20 units

Center of circle = (-1, 7)

Standard form of the equation of a circle is expressed in the center-radius form as:

$(x - h)^2 + (y - k)^2 = r^2$ ,

Where,

h = -1

k = 7

r = ½ of diameter = ½(20) = 10 units

Plug in the values into the equation

$(x - h)^2 + (y - k)^2 = r^2$

$(x - (-1))^2 + (y - 7)^2 = 10^2$

$(x + 1)^2 + (y - 7)^2 = 100$

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3 years ago

Which shows the expression x^2-1/x^2-x in simplest form

____ [38]

Answer:

$\large\boxed{\dfrac{x+1}{x}=1+\dfrac{1}{x}}$

Step-by-step explanation:

$\dfrac{x^2-1}{x^2-x}=(*)\\\\x^2-1=x^2-1^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(x-1)(x+1)\\\\x^2-x=(x)(x)-(x)(1)\qquad\text{use the distributive property}\\=x(x-1)\\\\(*)=\dfrac{(x-1)(x+1)}{x(x-1)}\qquad\text{cancel}\ (x-1)\\\\=\dfrac{x+1}{x}=\dfrac{x}{x}+\dfrac{1}{x}=1+\dfrac{1}{x}$

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3 years ago

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100+500-355+287-311=?<br> A. 22<br> B. 222<br> C. 223<br> D. 931

Ainat [17]

Answer:

Step-by-step explanation:

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3 years ago