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2 years ago

The volume of a cylinder is 1,0297 cubic

1 answer:

8 0

$\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=10297\\ h=21 \end{cases}\implies 10297=\pi r^2(21)\implies \cfrac{10297}{21\pi }=r^2 \\\\\\ \cfrac{1471}{3\pi }=r^2\implies \sqrt{\cfrac{1471}{3\pi }}=r\implies 12\approx r$

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08 Match the following

nataly862011 [7]

English. ???????????

8 0

3 years ago

Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu

Luda [366]

Answer:

11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

P(z ≤ -6) ≈ 9.86588×10^-10

and

P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

0.50^t = 0.000290372

t·log(0.50) = log(0.00290372) . . . . take logarithms

t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0

3 years ago

Find the value of x.

Ainat [17]

Answer:

$\textsf{x=22.5}$

Step-by-step explanation:

$\textsf{According to intersecting tangent - secant theorem,}$

$\textsf{x=1/2[(4x+5)-50]}$

$\textsf{2(x)=4x+5-50}$

$\textsf{2x=4x-45}$

$\textsf{2x-4x=-45}$

$\textsf{-2x=-45}$

$\textsf{x= -45/-2}$

$\textsf{x=22.5}$

$\textsf{OAmalOHopeO}$

5 0

3 years ago

A company has $6582 to give out in bonuses. An amount is to be given out equally to each of the 32 employees.

expeople1 [14]

A) His estimate is incorrect, since he has increased a figure to the amount that each employee would receive.

B) Rounded to the nearest dollar, each employee would receive $ 209.

Since a company has $ 6582 to give out in bonuses, and an amount is to be given out equally to each of the 32 employees, and A) a manager, Jake reasoned that since 32 goes into 64 twice, each employee will get about $ 2000 , to determine if his estimate is correct, and B) determine how much will each employee receive, rounded to the nearest whole dollar, the following calculations must be performed:

2000 x 32 = 64000
200 x 32 = 6400

Therefore, his estimate is incorrect, since he has increased a figure to the amount that each employee would receive.

6582/32 = X
208.68 = X

Therefore, rounded to the nearest dollar, each employee would receive $ 209.

Learn more about maths in brainly.com/question/8865479

4 0

2 years ago

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of app

AfilCa [17]

Answer:

$Q(t) = 4.5(1.013)^{t}$

The world population at the beginning of 2019 will be of 7.45 billion people.

Step-by-step explanation:

The world population can be modeled by the following equation.

$Q(t) = Q(0)(1+r)^{t}$

In which Q(t) is the population in t years after 1980, in billions, Q(0) is the initial population and r is the growth rate.

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of approximately 1.3%/year.

This means that $Q(0) = 4.5, r = 0.013$

$Q(t) = Q(0)(1+r)^{t}$

$Q(t) = 4.5(1.013)^{t}$

What will the world population be at the beginning of 2019 ?

2019 - 1980 = 39. So this is Q(39).

$Q(t) = 4.5(1.013)^{t}$

$Q(39) = 4.5(1.013)^{39} = 7.45$

The world population at the beginning of 2019 will be of 7.45 billion people.

6 0

3 years ago