To find the root, replace y with 0
X^2-12x+35=0
A=1 B=-12 C=35
B^2-4ac=(-12)^2 -4(1)(35)
=144 -140
=4
x=(-b+/- square root of b^2 -4ac) /over/ (2a)
Plug in the numbers
x=-(-12) sqr (-12)^2 4(1)(35) / (2)(1)
X=12 +/-sqr 4 / 2
Positive outcome
x=12 + sqr 4 / 2
x=12+2/2
x=7 <— this one
Negative outcome
x=12-2i/2
x=6-i
Vertex: (6,-1)
Answer:
16
Step-by-step explanation:
Given expression:
log(5x + 20) = 2
From the given expression, we are to find x;
Using the rule of logarithm, we can solve this problem;
logₐb = C
b = Cᵃ
So;
log(5x + 20) = 2
this is to base 10;
5x + 20 = 10²
5x = 100 - 20
5x = 80
x = 16
Answer:
a=4
Step-by-step explanation:
what minus 4=8? its 12. 12-4=8 so
what times 3 is 12? 4.
3*4=12
12-4=8
a=4
Answer:
a and c i think.
Step-by-step explanation:
Answer:
C. No, because one x-value corresponds to two different y-values
Step-by-step explanation:
An x-value cannot have two y-values. Hope this helps!
