When Acme Dynamite produces 250 units of output, its variable cost is $2,000, and its fixed cost is $500. It sells each unit of
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Answer:
Coupon rate = 0.04292 or 4.292%
Explanation:
To calculate the coupon rate of the bond, we will, use the formula for the price of the bond. As the bond is an annual bond, the coupon payment, number of periods and semi annual YTM will be,
Coupon Payment (C) = x
Total periods (n)= 8
r or YTM = 0.051 or 5.1%
The formula to calculate the price of the bonds today is attached.
948 = x * [( 1 - (1+0.051)^-8) / 0.051] + 1000 / (1+0.051)^8
948 = x * 6.437166243 + 671.7045216
948 - 671.7045216 = x * 6.437166243
276.2954784 / 6.437166243 = x
x = $42.92191128 rounded off to $42.92
Thus, the coupon payment on bond is $42.92
As the coupon payment is calculated by multiplying the coupon rate with the face value of the bond, then the coupon rate will be:
Coupon payment = face value * coupon rate
42.92 = 1000 * Coupon rate
Coupon rate = 42.92 / 1000
Coupon rate = 0.04292 or 4.292%
Answer:
Explanation:
The <em>probability mass function</em> (<em>PMF</em>), or <em>frequency function</em>, is the function that gives the probabilities that a <em>discrete random variable</em> take some values.
In this problem, it is requested the frequency function (PMF) for the <em>number of purchasers, among the next 15, who select a chain-driven model</em>.
Then , you need to find, the function that gives P(X=0), P(X=1), P(X=2), P(X=3), . . . up to P(X=15).
Such as any function, the frequency function can be presented as a formula, as a table, or as a graph.
Note that the statement represents a binomial disbribution in which success is that a customer select a chain-driven model and the fail is that a cusotmer does not select a chain-driven model.
The binomial probability for X = the number among the 15 purchasers who select the chain-driven model is given by the formula:
Where:
- n is the number of times the experiment is performed: 15 in our problem
- p is the probability of succes: 0.75 in our problem
- 1-p is the probability of fail: 0.25 in our problem
Then, substitute:
That is the frequency function.
If you want to give it as a table you must find P(X=1), P(X=2), P(X=3), . . . up to P(X=15) using that function. That is not part of the question.