I just need just a little help and I will just answer it

Mathematics

2 answers:

Kitty [74]3 years ago

8 0

Im sorry I have to give you the answer. i like subtracting. the answer is: 523836

DanielleElmas [232]3 years ago

5 0

The answer is 523,836

The process is shown in the image attached.

You might be interested in

Show how to make a ten to solve 13-7.

nevsk [136]

I think the answer is 6

8 0

3 years ago

Read 2 more answers

Mrs. Jackson gives the table below to her students.

krek1111 [17]

M= 20 because the rate of change is -3.

5 0

3 years ago

Read 2 more answers

Solve for all values of c in simplest form.<br> |C – 21 |= 12

Rina8888 [55]

Answer:

33, 9

Step-by-step explanation:

I33-21I=12

I9-21I=

I-12I=12

Every SUM of an absolute value will always be positive!!

5 0

3 years ago

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of <u>analytical geometry</u> is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$