Answer:
Mean
Step-by-step explanation:
Adding up and dividing to find the mean.
We simply add up all of the individual grades, get the total, and then divide by the number of students in the class.
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The expression is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power is; Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power
<h3>How to solve exponents?</h3>
We want to find the expression that is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power.
The sentence above can be expressed as;
((1.5⁵)/(0.7⁴))³
This can be broken down into;
[1.5^(5 * 3)]/(0.7^(4 * 3))
1.5¹⁵/0.7¹²
Looking at the options, the only correct one is;
Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power
Read more about Exponents at; brainly.com/question/11975096
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Answer:
.
Step-by-step explanation:
0.85x + 375 > 450
Answer:
Interquartile range
Step-by-step explanation:
Range = 32, 29
Median = -6, 3
Upper quatile = 2, 13
Interquartile range = 11, 23
==> Interquartile range has the greatest difference of 23-11 = 12
Answer:
.
Step-by-step explanation:
If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is 
.
Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)
Hence, β = - 3 and α + a = 1 and α - a = -3
Now, solving those two equations of α and a we get,
2α = - 2, ⇒ α = -1 and
a = 1 - α = 2.
Now, eccentricity of the hyperbola is given by ![b^{2} = a^{2}(e^{2} - 1) = 4[(\frac{5}{2} )^{2} -1] = 21](https://tex.z-dn.net/?f=b%5E%7B2%7D%20%3D%20a%5E%7B2%7D%28e%5E%7B2%7D%20%20-%201%29%20%3D%204%5B%28%5Cfrac%7B5%7D%7B2%7D%20%29%5E%7B2%7D%20-1%5D%20%3D%2021)
{Since 
given}
Therefore, the equation of the given hyperbola will be
. (Answer)
