Answer:
1/3 or 33.333333333%
Step-by-step explanation:
Two 9's
Six number possible
2/6= 1/3
Probability:
1/3 or 33.33333333%
Y= 3( x -2 )² - ( x-5 )² = 3 ( x² - 4 x + 4 ) - ( x² - 10 x + 25 ) =
= 3 x² - 12 x + 12 - x² + 10 x - 25=
= 2 x² - 2 x - 13 =
= 2 ( x² - x + 1/4 - 1/4 ) - 13 =
= 2 ( x - 1/2 )² - 1/2 - 26/2 = 2 ( x - 1/2 )² - 27/2
Answer: D)
The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.
<h3>What is the area of the circle and the square?</h3>
The area of the circle is
Ac = πr² = πd²/4 sq. units
Where r is the radius and d is the diameter of the circle.
The area of the square is given by
As = s² sq. units
Where s is the length of the side of a square.
<h3>Calculation:</h3>
It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.
So,
The area of pizza is
Ap = Ac = πd²/4 sq. units
= π(10)²/4
= 25π
= 78.54 sq. in
Then, the area of the square box with the length same as the diameter of the pizza is,
As = d²
= 10²
= 100 sq. in
Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.
Learn more about the area of a circle here:
brainly.com/question/15673093
#SPJ1
Answer:
The number of distinct arrangements is <em>12600</em><em>.</em>
Step-by-step explanation:
This is a permutation type of question and therefore the number of distinguishable permutations is:
n!/(n₁! n₂! n₃! ... nₓ!)
where
- n₁, n₂, n₃ ... is the number of arrangements for each object
- n is the number of objects
- nₓ is the number of arrangements for the last object
In this case
- n₁ is the identical copies of Hamlet
- n₂ is the identical copies of Macbeth
- n₃ is the identical copies of Romeo and Juliet
- nₓ = n₄ is the one copy of Midsummer's Night Dream
Therefore,
<em>Number of distinct arrangements = 10!/(4! × 3! × 2! × 1!)</em>
<em> = </em><em>12600 ways</em>
<em />
Thus, the number of distinct arrangements is <em>12600</em><em>.</em>
