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3 years ago

A simple random sample of 12 iPhone's being sold over the Internet had the

Mathematics

1 answer:

bearhunter [10]3 years ago

7 0

Answer:

The upper bound is 399.5

Step-by-step explanation:

Let's start by calculating the mean value of the distribution as the addition of all values given divided by 12:

Average = 289.75.

If the standard deviation is 56, then the upper bound in 95% the confidence interval for the mean price of the phones is going to be given by the mean value added to 56 times 1.96 (since 95% of the population is withing 1.96 times the standard deviation)

That is: 289.75 + 56 * 1.96 = 399.51

which rounded to one decimal place gives: 399.5

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Answer:

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3 years ago

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-w + 4(w+3) = -12 Please help

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vodomira [7]

Answer:

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Step-by-step explanation:

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3 years ago

There are four suits: clubs, diamonds, hearts, and spades, and the following cards appear in each suit: Ace, 2, 3, 4, 5,

fgiga [73]

Answer:

a. 4/52

b. 1/2

c. 1/4

d. 10/13

Step-by-step explanation:

In order to obtain the probabilities, you have to apply the formula:

$P(A) = \frac{n(A)}{n}$

Where P(A) is the probability of an event A, n(A) is the number of favorable outcomes for the event and n is the total number of possible outcomes.

For part a:

The total number of 4 cards is 4, because there are four suits and a card 4 for each suit

n(a)= 4

n=52 (The total number of cards)

P(a)=4/52

For part b:

There are two suits with black cards and 13 cards in each suit. Therefore, the number of black cards is: 13(2)=26

n(b)=26

n=52

P(b)=26/52=1/2

For part c:

The total number of cards with diamonds is 13

n(c)=13

n=52

P(c)=13/52=1/4

For part d:

There are 3 face cards in each suit, therefore the total number of face cards is (3)(4)=12. The rest of the cards are none-face cards, therefore:

n(d)= 52-12 = 40

n=52

P(d)=40/52=10/13

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3 years ago