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oee [108]
3 years ago
6

Order the numbers from least to greatest 15, 20, -13, -20, -9, 7

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
5 0
-20, -13, -9, 7, 13, 20
nasty-shy [4]3 years ago
4 0

Well, you would start with the negative (-) numbers.


-20,-13,-9.


I put -20 first because it is the smallest. Not to say that 20 is a small number  but, when it's negative the value goes down. -9 would be the biggest out of the negative numbers.


-20, -13, -9, 7, 15, 20


That's the completed line of numbers from ltg.


As you should know 7 is a small number because it's positive. Although, it is not the smallest out of the whole number set. In the whole number set, the biggest number is 20.


I will repeat the complete number set now: -20, -13, -9, 7, 15, 20.


I hope this helps!!


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Please help! Correct answer only, please!
sukhopar [10]

Answer: A. \left[\begin{array}{ccc}29&13\\13&10\\\end{array}\right]

Step-by-step explanation:

The question is asking us to find the product of the matrices. The key difference is the second A has a little <em>T</em> in the exponent. This <em>T</em> means transpose. You multiply A by the transpose of A. To find the transpose, you turn the rows into columns.

A^T=\left[\begin{array}{ccc}5&3\\2&-1\\\end{array}\right]

Now that we have our transpose, we can multiply the matrices.

\left[\begin{array}{ccc}5&2\\3&-1\\\end{array}\right] \left[\begin{array}{ccc}5&3\\2&-1\\\end{array}\right] =\left[\begin{array}{ccc}5*5+2*2&5*3+2(-1)\\3*5+2(-1)&3*3+(-1)(-1)\\\end{array}\right] =\left[\begin{array}{ccc}29&13\\13&10\\\end{array}\right]

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