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Lana71 [14]
3 years ago
14

Which is the completely factored form of 12x4 + 39x3 + 9x2?

Mathematics
2 answers:
mote1985 [20]3 years ago
5 0

Answer: The completely factored form will be

3x^2(4x+1)(x+3)

Step-by-step explanation:

Since we have given that

12x^4 + 39x^3 + 9x^2

We need to find the factored form,

So, here we go:

1) Taking out the common factor i.e. 3x² :

12x^4 + 39x^3 + 9x^2\\\\3x^2(4x^2+13x+3)

2) We get a quadratic equation , we will split the middle term:

(4x^2+13x+3)\\\\4x^2+12x+x+3=0\\\\4x(x+3)+1(x+3)=0\\\\(4x+1)(x+3)=0

3) Now, combine the all of the factors:

3x^2(4x+1)(x+3)

Hence, the completely factored form will be

3x^2(4x+1)(x+3)

Advocard [28]3 years ago
3 0
Hello,

12x^4+39x^3+9x²=x²(12x²+39x+9)=x²(12x²+36x+3x+9)=x²(4x(3x+9)+(3x+9))
=x²(3x+9)(4x+1)
=3x²(x+3)(4x+1)

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Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}
algol [13]

Solutions of 2cos(3x)= -\sqrt{2} in the interval from [0,2pi) is x =\frac{\pi}{12}  and x = \frac{23\pi}{12} .

<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

2cos(3x)= -\sqrt{2}

⇒ 2cos(3x)= -\sqrt{2}

⇒ \frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}

⇒ cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}

⇒ cos3x= \frac{-2}{2{\sqrt{2}}}

⇒ cos3x= \frac{-1}{{\sqrt{2}}}

⇒ cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})

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⇒ x=\pm \frac{\pi}{12}

Cosine General solution is :

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⇒ x = \frac{23\pi}{12}

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