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stich3 [128]
3 years ago
10

What's n = 3 x 45 for 5th grade math please cause I'm not sure how this math goes

Mathematics
1 answer:
Drupady [299]3 years ago
6 0
N=135. 45+45+45=135.
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Really need help please
zavuch27 [327]

Answer:

A

Step-by-step explanation:

1) Count the numbers larger than 5

(6,7,8,9,10)

2) Put it over a fraction

5/10

3)Simplify

1/2

3 0
3 years ago
An experiment was conducted to compare the use of iPads versus regular textbooks in teaching algebra to two classes of middle sc
lakkis [162]

Answer:

Step-by-step explanation:

Hello!

The objective is to determine if there is any difference between using iPads vs textbooks in teaching algebra.

Two middle school classes were selected, to eliminate any other source of variation, the same teacher taught both classes, and the materials were provided by the same author and publisher. After a month 10 students of each class were randomly selected and tested, their test scores were recorded:

X₁: test scores of students that used iPads to study.

n₁= 10

X[bar]₁= 86.8

S₁= 8.97

X₂: test scores of students that used regular textbooks to study.

n₂= 10

X[bar]₂= 79.5

S₂= 10.8

a.

H₀: μ₁=μ₂

H₁: μ₁≠μ₂

α:0.05

Assuming that both variables are normally distributed and the population variances are equal, the statistic to use is a Student t for two independent samples with pooled sample variance:

t_{H_0}= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }

Sa^2= \frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2}

Sa^2= \frac{9*80.4609+9*116.64}{10+10-2} = 98.55

Sa= 9.93

t_{H_0}= \frac{86.8-79.5}{9.93\sqrt{\frac{1}{10} +\frac{1}{10} } } = 1.64

p-value: 0.118364

The p-value is greater than the significance level so the decision is to not reject the null hypothesis. This means that there is no significant evidence between the scores of the two groups.

b.

95% CI

(X[bar]-X[bar])±t_{n_1+n_2-2;1-\alpha /2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }

t_{n_1+n_2-2;1-\alpha /2}= t_{18;1.975}= 2.101

(86.8-79.5)±2.101*(9.93\sqrt{\frac{1}{10} +\frac{1}{10} })

[-2.03; 16.63]

With a 95% confidence level, you'd expect that the interval [-2.03; 16.63] would contain the difference between the mean scores of the two classes.

c.

Considering that the null hypothesis wasn't rejected and that at the same level the confidence interval includes the zero, we can affirm that the format of the teaching materials, digital or regular textbooks, has no significant effect on the scores of the students.

I hope it helps!

3 0
3 years ago
Determine the area of the sector :
Shtirlitz [24]

Answer:

\boxed {\boxed {\sf a \approx207.35 \ in^2}}

Step-by-step explanation:

Since the central angle is given in degrees, we should use this formula to find the area of the sector:

a=\frac{\theta}{360} \times \pi r^2

The central angle is 165 degrees and the radius is 12 inches.

  • θ= 165
  • r= 12 in

Substitute the values into the formula.

a= \frac{165}{360} \times \pi (12 \ in)^2

Solve the exponent.

  • ( 12 in)² = 12 in * 12 in =144 in²

a= \frac{165}{360} \times \pi(144 \ in^2)

Multiply all the numbers together.

a= 207.345115137 \ in^2

Round to the nearest hundredth (two decimal places).

  • 207.345115137

The 5 in the thousandth place (in bold above) tells us to round the 4 in the hundredth place up to a 5.

a \approx207.35 \ in^2

The area of the sector is approximately <u>207.35 inches squared.</u>

7 0
3 years ago
31, -32, 33, -11, 5 least to greatest
garri49 [273]

Answer: -32, -11, 5, 31, 33

4 0
3 years ago
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A food processing plant is packaging 32oz bags of coffee beans. The tolerance is 0.25 ounces. 100 bags of coffee were weighed, a
lubasha [3.4K]

Answer: No

Step-by-step explanation:

6 0
3 years ago
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