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3 years ago

5

the number line goes from 0 to 1 and is subdivided into tenths Describe where youd locate the point 15/25

1 answer:

Vlada [557]3 years ago

5 0

Answer:

6/10

Step-by-step explanation:

Simplify 15/25 by dividing by 5/5

15/25 ÷ 5/5 = 3/5

Multiply 3/5 by 2/2 to convert to tenths

3/5 × 2/2 = 6/10

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Please help it is TIMED.

lions [1.4K]

Answer:

message it will be easy er to explain

Step-by-step explanation:

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3 years ago

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PLEASE help. The problem is to find the indicated sum.

alukav5142 [94]

The indicated sum is 350. The answer is 350 because the E or sigma is making you do (6j+2) ten times. Every time you do 6j+2 you start with j as 1 and add a 1 to j for every time you add. For example, [6(1)+2]+[6(2)+2]+[6(3)+2]...[6(10)+2].

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3 years ago

Solve x2 - 8x = 3 by completing the square. Which is the solution set

Simora [160]

Answer:

4\pm\sqrt{19}

Step-by-step explanation:

Move everything to left side

$x^{2} -8x -3 =0$

Now to solve this square equation we need to find Descriminant

$D=b^{2} -4ac=64+12=76$

As Descriminant D is greater than 0 then we have 2 solutions which we can calculate by this formula

$x_{1,2}=\frac{-b\pm\sqrt{D}}{2a} =\frac{8\pm2\sqrt{19}}{2}=4\pm\sqrt{19}$

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3 years ago

I will give brainleist

Goshia [24]

Let's write the equation in standard from

$y = mx + b$

Where,

m is slope or rate of change
b is the y-intercept or initial value

<h3>Let's start by finding slope⤵️</h3>

$\boxed{ \sf \: m = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1}}}$

x1, y1 = 0,12
x2, y2 = 1,13

$\tt \: m = \frac{13 - 12}{1 - 0}$

$\tt \: m = \frac{1}{1}$

$\tt \: m = 1$

b = 12

<h3>Equation⤵️</h3>

$\sf \: y = 1x + 12$

8 0

2 years ago

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Consider w=sqrrt2/2(cos(225°) + isin(225°)) and z = 1(cos(60°) + isin(60°)). What is w+ z expressed in rectangular form?

SVETLANKA909090 [29]

Answer:

Option (3)

Step-by-step explanation:

w = $\frac{\sqrt{2}}{2}[\text{cos}(225) + i\text{sin}(225)]$

Since, cos(225) = cos(180 + 45)

= -cos(45) [Since, cos(180 + θ) = -cosθ]

= - $\frac{\sqrt{2}}{2}$

sin(225) = sin(180 + 45)

= -sin(45)

= - $\frac{\sqrt{2}}{2}$

Therefore, w = $\frac{\sqrt{2}}{2}[-\frac{\sqrt{2}}{2}+i(-\frac{\sqrt{2}}{2})]$

= $-\frac{2}{4}(1+i)$

= $-\frac{1}{2}(1+i)$

z = 1[cos(60) + i(sin(60)]

= $[\frac{1}{2}+i(\frac{\sqrt{3}}{2})$

= $\frac{1}{2}(1+i\sqrt{3})$

Now (w + z) = $-\frac{1}{2}(1+i)+\frac{1}{2}(1+i\sqrt{3})$

= $-\frac{1}{2}-\frac{i}{2}+\frac{1}{2}+i\frac{\sqrt{3}}{2}$

= $\frac{(i\sqrt{3}-i)}{2}$

= $\frac{(\sqrt{3}-1)i}{2}$

Therefore, Option (3) will be the correct option.

3 0

3 years ago

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