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Tems11 [23]
2 years ago
5

the number line goes from 0 to 1 and is subdivided into tenths Describe where youd locate the point 15/25

Mathematics
1 answer:
Vlada [557]2 years ago
5 0

Answer:

6/10

Step-by-step explanation:

Simplify 15/25 by dividing by 5/5

15/25 ÷ 5/5 = 3/5

Multiply 3/5 by 2/2 to convert to tenths

3/5 × 2/2 = 6/10

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Answer:

message it will be easy er to explain

Step-by-step explanation:


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3 years ago
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PLEASE help. The problem is to find the indicated sum.​
alukav5142 [94]
The indicated sum is 350. The answer is 350 because the E or sigma is making you do (6j+2) ten times. Every time you do 6j+2 you start with j as 1 and add a 1 to j for every time you add. For example, [6(1)+2]+[6(2)+2]+[6(3)+2]...[6(10)+2].

Hope this helps.
8 0
3 years ago
Solve x2 - 8x = 3 by completing the square. Which is the solution set
Simora [160]

Answer:

4\pm\sqrt{19}

Step-by-step explanation:

Move everything to left side

x^{2} -8x -3 =0

Now to solve this square equation we need to find Descriminant

D=b^{2} -4ac=64+12=76

As Descriminant D is greater than 0 then we have 2 solutions which we can calculate by this formula

x_{1,2}=\frac{-b\pm\sqrt{D}}{2a} =\frac{8\pm2\sqrt{19}}{2}=4\pm\sqrt{19}

3 0
3 years ago
I will give brainleist
Goshia [24]

Let's write the equation in standard from

y = mx + b

Where,

  • m is slope or rate of change
  • b is the y-intercept or initial value

<h3>Let's start by finding slope⤵️</h3>

\boxed{ \sf \: m =  \frac{ y_{2} -  y_{1} }{ x_{2} -  x_{1}}}

  • x1, y1 = 0,12
  • x2, y2 = 1,13

\tt \: m =  \frac{13 - 12}{1 - 0}

\tt \: m =  \frac{1}{1}

\tt \: m = 1

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<h3>Equation⤵️</h3>

\sf \: y = 1x + 12

8 0
2 years ago
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Consider w=sqrrt2/2(cos(225°) + isin(225°)) and z = 1(cos(60°) + isin(60°)). What is w+ z expressed in rectangular form?
SVETLANKA909090 [29]

Answer:

Option (3)

Step-by-step explanation:

w = \frac{\sqrt{2}}{2}[\text{cos}(225) + i\text{sin}(225)]

Since, cos(225) = cos(180 + 45)

                          = -cos(45) [Since, cos(180 + θ) = -cosθ]

                          = -\frac{\sqrt{2}}{2}

sin(225) = sin(180 + 45)

             = -sin(45)

             = -\frac{\sqrt{2}}{2}

Therefore, w = \frac{\sqrt{2}}{2}[-\frac{\sqrt{2}}{2}+i(-\frac{\sqrt{2}}{2})]

                      = -\frac{2}{4}(1+i)

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z = 1[cos(60) + i(sin(60)]

  = [\frac{1}{2}+i(\frac{\sqrt{3}}{2})

  = \frac{1}{2}(1+i\sqrt{3})

Now (w + z) = -\frac{1}{2}(1+i)+\frac{1}{2}(1+i\sqrt{3})

                   = -\frac{1}{2}-\frac{i}{2}+\frac{1}{2}+i\frac{\sqrt{3}}{2}

                   = \frac{(i\sqrt{3}-i)}{2}

                   = \frac{(\sqrt{3}-1)i}{2}

Therefore, Option (3) will be the correct option.

3 0
3 years ago
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