Let the first term, common difference and number of terms of an AP are a, d and n respectively.
Given that, 9th term of an AP, T9 = 0 [∵ nth term of an AP, Tn = a + (n-1)d]
⇒ a + (9-1)d = 0
⇒ a + 8d = 0 ⇒ a = -8d ...(i)
Now, its 19th term , T19 = a + (19-1)d
= - 8d + 18d [from Eq.(i)]
= 10d ...(ii)
and its 29th term, T29 = a+(29-1)d
= -8d + 28d [from Eq.(i)]
= 20d = 2 × T19
Hence, its 29th term is twice its 19th term
Answer: The rock would still weigh 90lbs
Step-by-step explanation:
No, weight has being proven to reduce by the further you move from the center of the Earth. But since even the tallest buildings in the world or tallest mountains are a tiny fraction of the Earth’s radius, the difference in weight won’t be something that can be measured as it’s a tiny fraction. So the mass of the rock doesn’t change what changes is the gravitational force ( g ). So the rock would still end up weighing 90lbs even at the top of the tower because it is still within the earths atmosphere.
S = 2J - 1
R = J + 53
S - 25 = J + 25...S = J + 50
2J - 1 = J + 50
2J - J = 50 + 1
J = 51 <===Jason has 51 CD's
R = J + 53
R = 51 + 53
R = 104 <===Raoul has 104 CD's
S = 2J - 51
S = 2(51) - 1
S = 102 - 1
S = 101 <===Seth has 101 CD's
89 divided by 7 + 46^2 = 2128.71428571...
I hope this helps!